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The slope of the red line that is perpendicular to the green line is: -5/2.
<h3>What are the Slope Values of Perpendicular Lines?</h3>When one line lies perpendicular to another line, the slope of one must be the negative reciprocal of the other line.
<h3>What is the Negative Reciprocal of a Number?</h3>If given a number, i.e. a/b, the negative reciprocal of a/b would the opposite value of the reciprocal of a/b.
Reciprocal of a/b is b/a. Negative reciprocal of a/b would therefore be: -b/a.
Given that the slope of the green line is: 2/5. And it is perpendicular to the red line. The slope of the red line would be the negative reciprocal of 2/5.
Negative reciprocal of 2/5 is -5/2.
Therefore, the slope of the red line is: -5/2.
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Answer:
<u>Group the Variable's</u>:
2 x - 5 + 7 y - 3 = 9 x - 1 - y -8
2x -9x + 7y +y = -1 -8 +5 + 3
-7x + 8y = -1
<u><em>From this find x and y</em></u>
<u>For X</u>
-7x + 8y = -1
-7x = -1 -8y
7x = 8y + 1
x = (8y +1)/7
<u>For Y</u>
-7x + 8y = -1
8y = -1 +7x
y = (7x -1)/8