All categories

3 years ago

What the answer now hurry up and answer fast question

Mathematics

1 answer:

sergey [27]3 years ago

5 0

Answer:

927.0 cm²

Step-by-step explanation:

Step 1: find Z

m < Z = 180 - (28 + 118) (sum of ∆)

= 180 - 146

Z = 34°

Step 2: Find side XY using the law of sines

$\frac{XY}{sin(34)} = \frac{42}{sin(28)}$

Cross multiply

$XY*sin(28) = 42*sin(34)$

$XY*0.469 = 42*0.559$

Divide both sides by 0.469

$\frac{XY*0.469}{0.469} = \frac{42*0.559}{0.469}$

$XY = 50.06$

XY ≈ 50 cm

Step 3: find the area.

Area of ∆ = ½*XY*YZ*sin(Y)

XY ≈ 50 cm

= ½*50*42*sin(118)

= 25*42*0.8829

Area = 927.045

Area ≈ 927.0 cm² (nearest tenth)

You might be interested in

I need help ASAP can someone please help me right away

iragen [17]

Answer:

0 degrees?

Step-by-step explanation:

It looks perfectly even to me

7 0

3 years ago

Read 2 more answers

(Differential Equations) Put these equations in explicit form:

Nuetrik [128]

Answer:

1. $y= C(t*exp(-\frac{t^{2} }{2(2!)}+\frac{t^{4} }{4(4!)}-\frac{t^{6} }{6(6!)}+... ))}$

2. $t+C=ln(csc(y)-cot(y)$ $23. [tex]Assuming t as independent variable:F(r,t)=t+\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} =C\\Step-by-step explanation:1. Separable variables:[tex]\frac{dy}{dt}=\frac{y*cos(t) }{t}\\ \frac{dy}{y}= \frac{cos(t) }{t}dt\\ \int {\frac{dy }{y}} \, dt=\int {\frac{cos(t) }{t}} \, dt \\ln(y)-ln(C)=ln(t)-\frac{t^{2} }{2(2!)} +\frac{t^{4} }{4(4!)} -\frac{t^{6} }{6(6!)}+... \\y=C(t*exp(\frac{t^{2} }{2(2!)} +\frac{t^{4} }{4(4!)} -\frac{t^{6} }{6(6!)}+...))$

2. Separable variables

\frac{dy}{sin(y)}=dt\\ \int\ \frac{1}{sin(y)}} \, dy = \int\ 1} \, dt\\t+C=ln(csc(y)-cot(y))[/tex]

3. Homogeneous D.E

Rewriting:

$dr+(\frac{1}{m} exp(m+r)+r)dt=0\\\frac{dF}{dt}=1 -> F(r,t)=t+C(r)\\\frac{dF}{dy}=0+C'(r)= \frac{1}{m} exp(m+r)+r -> C(r)=\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} \\F(r,t)=t+\frac{1}{m} exp(m+r)+\frac{r^{2} }{2} =C\\$