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aliina [53]
3 years ago
7

Which expression is equivalent to √400 i^8 j^4 k^6

Mathematics
1 answer:
sergey [27]3 years ago
4 0

Answer:

20 i^{4} j^{2} k^{3}

Step-by-step explanation:

We have to simplify the following expression:

\sqrt{400i^{8} j^{4} k^{6} }

400 can be written as square of 20. The given expression can be simplified using the properties of exponents as shown below

\sqrt{20^{2} i^{8} j^{4} k^{6} }\\\\ =\sqrt{(20)^{2}(i^{4} )^{2} (j^{2} )^{2} (k^{3} )^{2} } \\\\=\sqrt{(20 i^{4} j^{2} k^{3} )^{2} } \\\\ =((20 i^{4} j^{2} k^{3} )^{2})^{\frac{1}{2} }\\\\ =20 i^{4} j^{2} k^{3}

Properties used:

x^{m \times n}=(x^{m})^{n} \\\\\sqrt{x} =x^{\frac{1}{2} }

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Need help asap plz help
Soloha48 [4]

Number three is D and number 4 is also D.

Explanation for number three:

When you divide 12 by 3, you get 4. This gives us the number we need to multiply 10 by to get our answer. 10 x 4 = 40

Explanation for number 4:

In the last question, the first step to getting to the answer was to divide the first two numbers. This is no different. When you divide 32.5 by 5, you get 6.5. Then you multiply 10 and 6.5, which equals 65.

8 0
3 years ago
What is the first step in simplifying the expression 11x-2-3(1-7x)^2/(x+1) ? square the binomial multiply the binomial by 3 divi
Delicious77 [7]

Answer:

Square the binomial :)


Step-by-step explanation:


6 0
3 years ago
The graph of f(x) = 2x + 1 is shown below. Explain how to find the average rate of change between x = 2 and x = 5. (10 points) G
levacccp [35]
First we need to find f(2) and f(5), which are 5 and 11 respectively; all you have to do is plug in 2 and 5.

Then, we use the following formula:

(f(b)-f(a))/(b-a),

where b and a are the largest and smallest x values respectively.

Finally, we plug our values in:

(11-5)/(5-2)=6/3=2

In fact, the average rate of change of any linear function is just the coefficient of the x term. Hope this helped!
4 0
3 years ago
Solve 4=1+x for the property of equality
ICE Princess25 [194]
The answer is x=3 is your answer
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Answer C is your answer
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