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3 years ago

What is the exponential form of root 17

Mathematics

2 answers:

shusha [124]3 years ago

4 0

Answer: $17^{1/2}$

This is 17 to the 1/2 power

The rule is

$\sqrt[n]{x} = x^{1/n}$

the n is the index of the root. For square roots, n = 2, so,

$\sqrt[n]{x} = x^{1/n}\\\\\sqrt[2]{17} = 17^{1/2}\\\\\sqrt{17} = 17^{1/2}\\$

monitta3 years ago

4 0

Answer:

17 as a root does not have a square divider other than a decimal.

Step-by-step explanation:

289 is the square of 17

17 x 17

17 is a prime number.

We cna use rounded to next 10th = 17 would then have 4.1 x 4.1

or closer is 4.1232 x 4.1232 = 17.0007

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Jace purchases a new motorcycle for $8000. The bike depreciates 12% every year.

Alex777 [14]

Answer:

We know that the original price of the bike was $8,000.

After one year, the price of the bike decays a 12%, then the new price of the bike is:

P(1) = $8,000*( 1 - 12%/100%) = $8,000*(1 - 0.12)

After another year, the price again decays a 12%, the new price will be:

P(2) = $8,000*(1 - 0.12)*(1 - 12%/100%) = $8,000*(1 - 0.12)*(1 - 0.12) = $8,000*(1 - 0.12)^2

We already can see the pattern here, after t years, the price of the bike will be:

P(t) = $8,000*(1 - 0.12)^t

With this equation, we can find the price of the bike after 5 years, where we only need to replace t by 5

We will get:

P(5) = $8,000*(1 - 0.12)^5 = $4,221.9

The price of the bike after 5 years is $4,221.9.

Now we want two equations to represent this, so we need another.

This is kinda trivial, because there is only one equation that represents this, so we only can rewrite our equation in another form.

We could say that the price of the bike after t years is:

P(t) = $8,000*(0.88)^t

or something like:

P(t) = $7040*(0.88)^(t - 1)

Where i multiplied the initial value by 0.88, and then reduced the exponent by one.

3 0

2 years ago

Allometric relations often can be modeled by f(x)= x^b, where a and b are constants. One study showed that for a male fiddler

dolphi86 [110]

Answer:

a) $f(2)= 0.448 (2)^{1.21}= 1.036 grams$

b) $0.5 = 0.448 x^{1.21}$

Dividing both sides by 0.448 we got:

$\frac{0.5}{0.448} = x^{1.21}$

We can appy the exponent $\frac{1}{1.21}$ in both sides of the equation and we got:

$(\frac{0.5}{0.448})^{\frac{1}{1.21}} = x= 1.095grams$

Step-by-step explanation:

For this case we know the following function:

$f(x) = 0.448 x^{1.21}$

The notation is: x is the weight of the crab in grams, and the output f(x) is the weight of the claws in grams.

Part a

For this case we just need to replace x = 2 gram in the function and we got:

$f(2)= 0.448 (2)^{1.21}= 1.036 grams$

Part b

For this case we know tha value for $f(x) =0.5$ and we want to find the value of x who satisfy this condition:

$0.5 = 0.448 x^{1.21}$

Dividing both sides by 0.448 we got:

$\frac{0.5}{0.448} = x^{1.21}$

We can appy the exponent $\frac{1}{1.21}$ in both sides of the equation and we got:

$(\frac{0.5}{0.448})^{\frac{1}{1.21}} = x= 1.095grams$

8 0

3 years ago

Suppose that the division N/5 leaves a remainder of 4, and the division N/2 leaves a remainder of 1, what is the ones digit on N

Tju [1.3M]

Since N/2 leaves a remainder, N must be odd and ends with 1, 3, 5, 7, or 9.

N/5 also leaves a remainder, so N is not divisible by 5, so it does not end in 5.

The only correct choice is then 9, since

1 = 0•5 + 1 and 1 = 0•2 + 1

3 = 0•5 + 3 and 3 = 1•2 + 1

7 = 1•5 + 2 and 7 = 3•2 + 1

9 = 1•5 + 4 and 9 = 4•2 + 1

Alternatively, the given information is equivalent to saying

$N\equiv 4\pmod5\\\\N\equiv1\pmod2$

Then you can use the Chinese remainder theorem to find N.

7 0

2 years ago

Please give answer asap

Drupady [299]

Answer:

9 < √88 < 10

Second one

Step-by-step explanation:

√81 = 9

√100 = 10

√88 is between √81 and √100

√81 < √88 < √100

9 < √88 < 10

8 0

3 years ago

Read 2 more answers

What is the value of x? Please help! Thanks!

leonid [27]

Answer:

x=75

Step-by-step explanation:

We can use proportions to solve this problem. Put the side of the small triangle over the side of the large triangle.

42 50

------ = ----------

42+63 50+x

42 50

------ = ----------

105 50+x

Using cross products

42(50+x) = 50*(105)

2100+42x = 5250

Subtract 2100 from each side

2100-2100+42x = 5250-2100

42x =3150

Divide by 42

42x/42 = 3150/42

x = 75

8 0

3 years ago