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3 years ago

What percent is 608 of 845

2 answers:

6 0

Well, we want to know what percent 608 is of 845, so to solve that, let's call 845 100%, as we're solving it terms of 845. 845 is 100%, then it follows that 8.45 is 1%. Now we can see how many 8.45's go into 608, which comes out to 71.95266...%, which can be rounded nicely to 72%

krek1111 [17]3 years ago

3 0

To answer this, you can use this equation:
Part = percent • whole.
In this situation, your part is 608 and your whole is 845.
Your equation is: 608= 845x.
Now, you need to divide 608 by 845, giving you 0.71952... To turn this into a percent, you move the decimal two places to the right. Your percent is 72.952... You would have to round this to 72.95%.

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What is the equation of the line that passes through the points (-1, 3) and (1, 11)

lina2011 [118]

Answer: To find the slope of this line, you would use the fomula

y2 - y1/ x2 - x1

11 - 3 / 1 - (-1)=

8/2

The slope of your line would be 4

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3 years ago

Write the inequality given in the diagram below

11111nata11111 [884]

Answer:

x ≥ - 1

Step-by-step explanation:

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x ≥ - 1

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1 year ago

A school club raises $506 to spend on a field trip. There are 23 people going on the trip. How much money did the club raise for

saveliy_v [14]

Answer:

$22

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Money raised = $506.

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Money per person = $22

3 0

2 years ago

Read 2 more answers

A ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is h-48t -16t^2.

Marat540 [252]

Answer:

36 feet.

Step-by-step explanation:

We have been given that a ball is thrown upward from ground level. Its height h, in feet, above the ground after t seconds is $h(t)=-48t -16t^2$ . We are asked to find the maximum height of the ball.

We can see that our given equation is a downward opening parabola, so its maximum height will be the vertex of the parabola.

To find the maximum height of the ball, we need to find y-coordinate of vertex of parabola.

Let us find x-coordinate of parabola using formula $x=-\frac{b}{2a}$ .

$x=-\frac{-48}{2(-16)}$

$x=-\frac{48}{32}$

$x=-\frac{3}{2}$

So, the x-coordinate of the parabola is $-\frac{3}{2}$ . Now, we will substitute $x=-\frac{3}{2}$ in our given equation to find y-coordinate of parabola.