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3 years ago

10

Sam made a password that consists of one letter followed by two digits. The two digits are different. How many possible password

s did Sam choose from?
90, 720, 2,340, or 260?

2 answers:

slega [8]3 years ago

8 0

Answer:

720

Step-by-step explanation:

salantis [7]3 years ago

3 0

Sam choose so that’s the answer720

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F as a function of x is equal to the square root of quantity 6 x plus 9 , f as a function of x is equal to the square root of qu

Elis [28]

Answer:

A. $\sqrt{6x+9} +\sqrt{6x-9}$

Step-by-step explanation:

We are given the functions f(x) and g(x) as,

$f(x)=\sqrt{6x+9}$

$g(x)=\sqrt{6x-9}$

It is required to find the function ( f+g ) i.e. ( f+g ) (x)

So, $(f+g)(x)=f(x)+g(x)$

i.e. $(f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}$

Hence, we get that $(f+g)(x)=\sqrt{6x+9}+\sqrt{6x-9}$ .

So, the first option is correct.

4 0

3 years ago

(25 points!!!!!) solve for <2

stiv31 [10]

Step-by-step explanation:

135 = <2 + 86 [exterior angle of triangle is equal to the sum of its oppsite two interior angles]

or, <2 = 135 - 86

so, <2 = 49°

8 0

2 years ago

Explain how to find the measure of X without finding the measure of its supplement first

Serggg [28]

Is there a picture or something that could at least tell us what is your question

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3 years ago

Read 2 more answers

Solve P=2G + 2M for G.<br> G=

shusha [124]

Answer:

$G=\frac{P-2M}{2}$

Step-by-step explanation:

$P=2G+2M \\ \\ P-2M=2G \\ \\ G=\frac{P-2M}{2}$

6 0

1 year ago

Evaluate using <br> Definite integrals

swat32

Since $[0,4]=[0,1]\cup(1,4]$ , we can rewrite the integral as

$\displaystyle \int_0^1f(t)\;dt + \int_1^4 f(t)\; dt$

Now there is no ambiguity about the definition of f(t), because in each integral we are integrating a single part of its piecewise definition:

$\displaystyle \int_0^1f(t)\;dt = \int_0^11-3t^2\;dt,\quad \int_1^4 f(t)\; dt = \int_1^4 2t\; dt$

Both integrals are quite immediate: you only need to use the power rule

$\displaystyle \int x^n\;dx=\dfrac{x^{n+1}}{n+1}$

to get

$\displaystyle \int_0^11-3t^2\;dt = \left[t-t^3\right]_0^1,\quad \int_1^4 2t\; dt = \left[t^2\right]_1^4$

Now we only need to evaluate the antiderivatives:

$\left[t-t^3\right]_0^1 = 1-1^3=0,\quad \left[t^2\right]_1^4 = 4^2-1^2=15$

So, the final answer is 15.

4 0

3 years ago