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3 years ago

9

If a bus travels 20 km in 30 minutes. What is the average speed of the bus?

2 answers:

sattari [20]3 years ago

4 0

<span>So we need to find the average speed of the bus that travels 20 km in 30 minutes. Average speed is defined as: Average speed=distance travelled/time taken or: v=s/t. We know s=20 km and t=30 minutes=0.5h. So after we input our numbers in the equation, we get: v=20km/0.5h=40km/h. So the correct answer is C) 40km/h.</span>

tatiyna3 years ago

4 0

Answer:c

Step-by-step explanation:

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1.61 is the correct answer

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3 years ago

The perimeter of a square flower bed is 100 feet. what is the area of the flower bed in sqaure feet

Semmy [17]

Answer:

A =625 ft^2

Step-by-step explanation:

The perimeter of a square is

P = 4s where s is the side length

100 =4s

Divide each side by 4

100/4 = 4s/4

25 = s

A = s^2 for a square

A = 25^2

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8 0

3 years ago

A certain college graduate borrows 7864 dollars to buy a car. The lender charges interest at an annual rate of 13%. Assuming tha

White raven [17]

Answer:

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = =$1573.17

Step-by-step explanation:

Consider A represent the balance at time t.

A(0)=$ 7864.

r=13 % =0.13

Rate payment = $k

The balance rate increases by interest (product of interest rate and current balance) and payment rate.

$\frac{dB}{dt} = rB-k$

$\Rightarrow \frac{dB}{dt} - rB=-k$ .......(1)

To solve the equation ,we have to find out the integrating factor.

Here p(t)= the coefficient of B =-r

The integrating factor $=e^{\int p(t) dt$

$=e^{\int (-r)dt$

$=e^{-rt}$

Multiplying the integrating factor the both sides of equation (1)

$e^{-rt}\frac{dB}{dt} -e^{-rt}rB=-ke^{-rt}$

$\Rightarrow e^{-rt}dB - e^{-rt}rBdt=-ke^{-rt}dt$

Integrating both sides

$\Rightarrow \int e^{-rt}dB -\int e^{-rt}rBdt=\int-ke^{-rt}dt$

$\Rightarrow e^{-rt}B=\frac{-ke^{-rt}}{-r} +C$ [ where C arbitrary constant]

$\Rightarrow B(t)=\frac{k}{r} +Ce^{rt}$

Initial condition B=7864 when t =0

$\therefore 7864= \frac{k}{r} - Ce^0$

$\Rightarrow C= \frac{k}{r} -7864$

Then the general solution is

$B(t)=\frac{k}{r}-( \frac{k}{r}-7864)e^{rt}$

To determine the payment rate, we have to put the value of B(3), r and t in the general solution.

Here B(3)=0, r=0.13 and t=3

$B(3)=0=\frac{k}{0.13}-( \frac{k}{0.13}-7864)e^{0.13\times 3}$

$\Rightarrow- 0.48\frac{k}{0.13} +11614.98=0$

⇒k≈3145.72

Therefore rate of payment = $ 3145.72

Therefore the rate of interest = ${(3145.72×3)-7864}

=$1573.17

4 0

4 years ago

I don't get it please help and show me how to do it

Solnce55 [7]

Answer:

Step-by-step explanation:

You plug in the given values and compute s:

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s = 10*1/2 + 1/2*-2*(1/2)^2

= 5 + -1*1/4

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7 0

3 years ago

Which expression are equivalent to 3p + 15? choose ALL THAT APPLY

german

The equivalent expressions are: A and C

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3 years ago

Read 2 more answers