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sp2606 [1]
3 years ago
9

20+17v=-6+15v solve for v

Mathematics
2 answers:
oksano4ka [1.4K]3 years ago
4 0
20+17v=-6+15v
Subtract 20 from both sides.
17v=-26+15v
Subtract 15v from both sides.
2v=-26
Divide -26 by2.
v=-13
Ksenya-84 [330]3 years ago
3 0
S20+17v=-6+15v
try to get the placeholder on only one side
subtract 15v from both sides
20+2v=-6
subtract 20 from both sides
2v=-26
divide both sides by 2
v=-13
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The Hoover Dam generates an average of about 11,506,000 kilowatt-hours of electricity per day.
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161,084,000

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7 x 11,506,000 = 80,542,000

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Find f(-2) for f(x) = 3.2.<br> O A. 2/1<br> OB.<br> 36<br> O C. -36<br> OD. -12<br> 3/4
valina [46]

Answer:

3/4 (A)

Step-by-step explanation:

replace x with -2 in the function

3 · 2^-2  = 3 · 0.25

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1 year ago
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You deposit $2000 into an account that pays 6% compounded monthly. a. How much money will you have in the account after 1 year?
Masteriza [31]

We have a deposit of $2000 into an account that pays 6% compounded monthly, after a year we will have:

\begin{gathered} \text{account}_{\text{year}}=2000\cdot(1+\frac{6}{100})^{12} \\ \text{account}_{\text{year}}=4024.4 \end{gathered}

The effective annual yield (EAY) will be:

\text{EAY}=\frac{account_{year}}{2000}-1=\frac{4024.14}{2000}-1=1.0122

The EAY is 101.22%

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9 months ago
Triangle ABC is a right triangle. The sides measure AB = 3 and BC = 4. Use the Pythagorean theorem to find CA. A. CA = 25 B. CA
Vesna [10]

Answer:

  CA = 5

Step-by-step explanation:

Since the sides are 3 and 4, we recognize this as a 3:4:5 right triangle, with CA = 5. Using the Pythagorean theorem confirms this:

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  CA² = 3² +4² = 9 +16 = 25

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5 0
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A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
Kay [80]

Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

P(\dfrac{X}{Y}) = 60\% = 0.6

P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

P(Y) = 0.01

Thus, P(Y') \ will\ be = 1 - P(Y)

P(Y') = 1 - 0.01

P(Y') = 0.99

The probability of cheating & the evidence is present is = P(YX)

P(YX) = P(\dfrac{X}{Y}) \ P(Y)

P(YX) =0.6 \times 0.01

P(YX) =0.006

The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

P(\dfrac{Y}{X}) = \dfrac{P(0.006)}{P(0.006099)}

P(\dfrac{Y}{X}) = 0.9838

5 0
2 years ago
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