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3 years ago

diane draws abtuse, isoscules triangle with one of the angle mesuring 35. what i sthe messer of teh obtuse triangle

Mathematics

1 answer:

RoseWind [281]3 years ago

5 0

Answer:

All angle = (110°, 35°, 35°)

Step-by-step explanation:

Given:

Triangle is a Obtuse isosceles triangle

One angle = 35°

Find:

All angle

Computation:

In the Obtuse isosceles triangle, one angle is obtuse and the other two angles are acute so, two equal angles are 35°

So,

Sum of angle property

x + 35° + 35° = 180°

x = 110°

Obtuse angle = 110°

All angle = (110°, 35°, 35°)

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4 years ago

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3 years ago

A standard piece of paper is 0.05 mm thick. Let's imagine taking a piece of paper and folding the paper in half multiple times.

tatyana61 [14]

Answer:

(a) $g(n)=0.05\cdot 2^n$

(b) $g^{-1}(n)=\log_{2}20g(n)$

Step-by-step explanation:

Part A

The paper's thickness = 0.05mm

When the paper is folded, its width doubles (increases by 100%).

The thickness of the paper grows exponentially and can be modeled by the function:

$g(n)=0.05(1+100\%)^n\\\\g(n)=0.05\cdot 2^n$

Part B

$g(n)=0.05\cdot 2^n\\2^n=\dfrac{g(n)}{0.05}\\ 2^n=20g(n)\\$Changing to logarithm form, we have:\\\log_{2}20g(n)=n\\$Therefore:\\g^{-1}(n)=\log_{2}20g(n)$

Part C

If the thickness of the paper, g(n)=384,472,300,000 mm

Then:

$g^{-1}(n)=\log_{2}20g(n)\\g^{-1}(n)=\log_{2}20\times 384,472,300,000\\=\dfrac{\log 20\times 384,472,300,000}{\log 2} \\g^{-1}(n)=42.8 \approx 43\\n=43$

You must fold the paper 43 times to make the folded paper have a thickness that is the same as the distance from the earth to the moon.

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3 years ago

Find the location of A' given that A is (7, 1).

SSSSS [86.1K]

Answer:

We conclude that the location of A' is: A'(6, 1)

Step-by-step explanation:

Given

A(7, 1)

To determine:

The location of A'

Translation Rule:

As we have to translate 1 unit left, meaning we need to subtract 1 unit from the x-coordinate of point A(7, 1) to determine the location of A'.

In other words, the translation rule is:

A(x, y) → A'(x-1, y)

A(7, 1)

A(7, 1) → A'(7-1, 1) = A'(6, 1)

Therefore, we conclude that the location of A' is: A'(6, 1)

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3 years ago