The ratio of the volume of fruit juice to the volume of smoothies served at a party was 4 1/2: 2.4. There were 35 liters more fr
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To solve the question we must know about the conservation of momentum.
<h2>Conservation of Momentum</h2>
According to the law of conservation of momentum, when two bodies collide with each other then their momentum is conserved if no external force acts on the system. therefore, the combined momentum of the two objects before collision will be equal to the combined momentum of the two objects after the collision.
the momentum of the two objects before the collision
= momentum of the two objects after the collision
The mass of the box is 0.30141 kg.
<h2>Explanation</h2>Given to us
- Mass of racquetball, m = 0.0427 kg,
- Velocity of racquetball before Collision,
= 22.3 m/s,
- Velocity of box before Collision,
= 0 m/s,
- Velocity of racquetball after Collision,
= 11.5 m/s,
- Velocity of box after Collision,
= 1.53 m/s,
Let the mass of the box be M.
<h3>Conservation Of Momentum</h3>Momentum before collision = Momentum after collision
given, the box was stationary before the collision,
Substituting the values,
Hence, the mass of the box is 0.30141 kg.
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