Answer:
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a randomly selected individual will be between 185 and 190 pounds?
This probability is the pvalue of Z when X = 190 subtracted by the pvalue of Z when X = 185. So
X = 190



has a pvalue of 0.8944
X = 185



has a pvalue of 0.7357
0.8944 - 0.7357 = 0.1587
15.87% probability that a randomly selected individual will be between 185 and 190 pounds
I)
8 - 3x = 23
-3x = 15
x = -5
ii)
5x - 16 = 34
5x = 50
x = 10
iii)
2 - 5x = -3
-5x = -5
x = 1
A = 1/2bh...for h
multiply both sides by 2
2A = bh
now divide both sides by b
(2a)/b = h
Answer:

Step-by-step explanation:
Let h be the cylinders height and r the radius.
-The volume of a cylinder is calculated as:

-Since the cone is within the cylinder, it has the same radius as the cylinder.
-Let
be the height of the cone.
-The area of a cone is calculated as;

The volume of the solid section of the cylinder is calculated by subtracting the cone's volume from the cylinders:

Hence, the approximate area of the solid portion is 
Answer:
The answer is 116
Step-by-step explanation:
Because this shape is a quadrilateral, so the sum of the angles of a quadrilateral is a total of 360 degrees. So i added 90 + 90 + 64 = 244. And 360 - 244 = 116.