4 years ago

What is the value of i20+-?

Mathematics

1 answer:

Svetach [21]4 years ago

4 0

i^20+1

i= /2

i^2= -1

i^3= -i

i^4= 1

for every four it repeat itself.

4, 8, 12, 16, 20.

therefore i^20=1

1+1=2

You might be interested in

What differentiable functions have an arc length on the interval [a, b] given by the following integrals? Note that the answers

Dafna1 [17]

Answer:

a) $\pm 8\frac{x^{5}}{5}+C$

b) $\pm 4 sin(2x) + C$

Step-by-step explanation:

Given integrals are:

$a) \int\limits^a_b {\sqrt{{1+64x^{8}} } \, dx$ ---(1)

$b) \int\limits^a_b {\sqrt{1+64cos^{2}(2x)} } \, dx$ ---- (2)

Standard form

$L= \int\limits^a_b {\sqrt{1+(f'(x))^{2}} } \, dx$

compare (1) with standard form

$[f'(x)]^{2} = 64x^{8}\\f'(x)=\pm 8x^{4}\\f(x)= \pm8\frac{x^{5}}{5}+C$

Compare (2) with standard form

$[f'(x)]^{2}=64cos^{2}(2x)\\f'(x)= \pm 8cos(2x)\\f(x)=\pm 8\frac{sin(2x)}{2}+C\\f(x)= \pm 4sin(2x)+C$

5 0

3 years ago

Answer number 4 this is due tomorrow

ikadub [295]

Answer:

The next mark should be at (3,-3)

5 0

3 years ago

Enter your answer and show all the steps that you use to solve this problem in the space provided.

SOVA2 [1]

Answer:

The value of the expression at b = -2 is thus -6

Step-by-step explanation:

We have been given the expression;

$|b|+b^{3}$

and we are required to evaluate the expression for b = -2

We simply substitute b with -2 in the given expression and simplify;

$|-2|+(-2)^{3}\\\\|-2|=2\\\\(-2)^{3}=-2*-2*-2=-8\\ \\|-2|+(-2)^3=2+(-8)=2-8=-6$

3 0

3 years ago

What is the solution to the trigonometric inequality sin(x) > cos(x) over the interval 0 ≤ x ≤ 2pi radians?

suter [353]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve C = 2πr (solve for "r")<br> C = 15<br><br> How dodo solve it

Y_Kistochka [10]

Substitute C for 15 then divide 2(pi). (pi)= 3.14
15 / 2(3.14)
15 / 6.28
r = 2.39
I hope this helped love!!

4 0

4 years ago

Read 2 more answers