All categories

3 years ago

!!20 POINTS!! Find AC

Mathematics

2 answers:

kipiarov [429]3 years ago

6 0

Answer:

it's just 5 points LOLLLLL

alisha [4.7K]3 years ago

4 0

Answer:

A. 12

Step-by-step explanation:

a = -7

b = -4

c = 5

ignore B. counting should be till the desired grid which is C

AC = 7 + 5

AC = 12

You might be interested in

After eating at your favorite restaurant, you know that the bill before tax is $52.60 and that the sales tax rate is 8%. you dec

rusak2 [61]

Answer:

$67.32

Step-by-step explanation:

52.6 multiplied by .08 equals 4.2

52.6 multiplied by .2 equals 10.52

4.2 plus 10.52 equals 14.72

52.6 plus 14.62 equals 67.32

6 0

3 years ago

Which number line represents the solution set for the inequality - 글 x 2 47

aleksandr82 [10.1K]

Answer:

dufenschmertz evil incorporated...

Step-by-step explanation:

after hours ;)

oh ma goawd he on x gaems mode

7 0

3 years ago

What is the relationship between 9.125×10−3 and 9.125×102?

gavmur [86]

Answer:

100,000 then its less

good luck

8 0

3 years ago

Can someone please help me please!!!!!!!!!

Alla [95]

What do they mean by describe the diagram

7 0

3 years ago

A hiker is hiking in a valley. The height of the valley is h(x,y)=4x2+y2 where x and y are the east-west and north-south distanc

Ainat [17]

Answer:

A. $\frac{\partial{h}}{\partial{t}}=0$

Step-by-step explanation:

A. The problems asked for 2 ways to solve it, expanding the equation with the substitution x(t)=2 cos(t) and y(t)=4 sin(t) to differentiate it . The other way is by chain rule.

Expanding and differentiating:

We start by substituting x(t)=2 cos(t) and y(t)=4 sin(t) in h(x,y)=4x2+y2:

$h(x,y)=4x^{2}+y^{2}= 4(2cos(t))^{2}+(4sin(t))^{2}\\h(x,y)=4(4cos^{2}(t))+(16sen^{2}(t))\\h(x,y)=16cos^{2}(t)+16sen^{2}(t)=16(sen^{2}(t)+cos^{2}(t))\\h(x,y)=16$

So, in the path that the hiker chose:

$\frac{\partial{h}}{\partial{t}}=0$

Chain rule:

We start differentiating h(x,y) using chain rule as follows:

$\frac{\partial{h}}{\partial{t}}= \frac{\partial{h}}{\partial{x}}\frac{\partial{x}}{\partial{t}}+\frac{\partial{h}}{\partial{y}}\frac{\partial{y}}{\partial{t}}$

Now, it´s easy to find all these derivatives:

$\frac{\partial{h}}{\partial{x}}=8x\\\frac{\partial{x}}{\partial{t}}=-2sin(t)\\\frac{\partial{h}}{\partial{y}}=2y\\\frac{\partial{y}}{\partial{t}}=4cos(t)$

Now we replace them in the chain rule, with the replacement x=2cos(t) and y=4sin(t) in the x,y that are left and we operate everything:

$\frac{\partial{h}}{\partial{t}}= 8x(-2sin(t))+2y(4cos(t)$

$\frac{\partial{h}}{\partial{t}}= 8(2cos(t))(-2sin(t))+2(4sin(t))(4cos(t)$

$\frac{\partial{h}}{\partial{t}}= -32cos(t)sin(t)+32sin(t)cos(t)$

$\frac{\partial{h}}{\partial{t}}= 0$

This will be our answer

6 0

3 years ago