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serg [7]
2 years ago
5

write the equation of the line that has a slope of three and a Y intercept of eight in slope intercept form

Mathematics
2 answers:
MariettaO [177]2 years ago
4 0

Answer:

y = 3x + 8

Step-by-step explanation:

y = mx + b

m is the slope

b is the y intercept

KiRa [710]2 years ago
3 0

Answer:

Step-by-step explanation:

slope (m) = 3

Y intercept c = 8

Slope intercept form: y= mx +c

    y = 3x + 8

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The awnser is 24.0 or 24
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3 years ago
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Which of the following measurements is least precise, and how many significant digits does it
gtnhenbr [62]

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50.25 cm trust me

Step-by-step explanation:

5.25 cm

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2 years ago
For the following telescoping series, find a formula for the nth term of the sequence of partial sums
gtnhenbr [62]

I'm guessing the sum is supposed to be

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}

Split the summand into partial fractions:

\dfrac1{(5k-1)(5k+4)}=\dfrac a{5k-1}+\dfrac b{5k+4}

1=a(5k+4)+b(5k-1)

If k=-\frac45, then

1=b(-4-1)\implies b=-\frac15

If k=\frac15, then

1=a(1+4)\implies a=\frac15

This means

\dfrac{10}{(5k-1)(5k+4)}=\dfrac2{5k-1}-\dfrac2{5k+4}

Consider the nth partial sum of the series:

S_n=2\left(\dfrac14-\dfrac19\right)+2\left(\dfrac19-\dfrac1{14}\right)+2\left(\dfrac1{14}-\dfrac1{19}\right)+\cdots+2\left(\dfrac1{5n-1}-\dfrac1{5n+4}\right)

The sum telescopes so that

S_n=\dfrac2{14}-\dfrac2{5n+4}

and as n\to\infty, the second term vanishes and leaves us with

\displaystyle\sum_{k=1}^\infty\frac{10}{(5k-1)(5k+4)}=\lim_{n\to\infty}S_n=\frac17

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3 years ago
On a piece of paper, use a protractor to construct a triangle with angle measures of 40° and 60º.
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There are 180 degrees in a triangle so it is 80 degrees

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Given A(2, 3) B(1, 4) C(1, 3) D(-2, 2). How are AB and CD related?
kondaur [170]

The vector AB is not related with the vector CD as k is not the same for each pair of components.

<h3>Are two vectors similar?</h3>

In this question we must prove if the vector AB is a multiple of the vector CD, that is:

\overrightarrow{AB} = k \cdot \overrightarrow {CD}

\vec B - \vec A = k \cdot [\vec D - \vec C]

(1, 4) - (2, 3) = k · [(- 2, 2) - (1, 3)]

(- 1, 1) = k · (- 3, - 1)

Hence, the vector AB is not related with the vector CD as k is not the same for each pair of components.

To learn more on vectors: brainly.com/question/13322477

#SPJ1

3 0
2 years ago
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