Find a common factor 3 and 12 in order to cancel it out:
Greatest common divisor of 3,12 is 3
Factor out 3 from the numerator and the denominator:
hope this helps!
Answer:
x=3 and y= -1
Step-by-step explanation:
Step 1: Solve2x+y=5 for y:
2x+y=5
2x+y+−2x=5+−2x(Add -2x to both sides)
y=−2x+5
Step 2: Substitute−2x+5foryin5x+3y=12:
5x+3y=12
5x+3(−2x+5)=12
−x+15=12(Simplify both sides of the equation)
−x+15+−15=12+−15(Add -15 to both sides)
(Divide both sides by -1)
x=3
Step 3: Substitute3forxiny=−2x+5:
y=−2x+5
y=(−2)(3)+5
y=−1(Simplify both sides of the equation)
Answer:
x=3 and y=−1
The first one is already in slope intercept the other one is y=-2x+9
Answer:
the answer 45 degree ,hope this helps you
Answer:
a) aₙ = 4.(2)^n-1
b) aₙ = 2+3(n-1)
c) aₙ = 3+4(n-1)
d) aₙ = 3.(4)^n-1
Step-by-step explanation:
a) a geometric sequence with first term of 4 and a common ratio of 2
aₙ = ar^n-1
where a is the first term and r is the common ratio
aₙ = 4.(2)^n-1
Comparing with the standard form:
1st term = 4
Common ratio = 2
b) an arithmetic sequence with a first term of 2 and a common difference of 3
The standard form of arithmetic sequence is:
aₙ = a₁ + d(n-1)
where a₁ is the first term and d is the common difference
Given: aₙ = 2+3(n-1)
Comparing with standard equation
First term = 2
Common difference = 3
c) an arithmetic sequence with a first term of 3 and a common difference of 4
The standard form of arithmetic sequence is:
aₙ = a₁ + d(n-1)
where a₁ is the first term and d is the common difference
Given: aₙ = 3+4(n-1)
Comparing with standard equation
First term = 2
Common difference = 3
d) a geometric sequence with first term of 3 and a common ratio of 4
aₙ = ar^n-1
where a is the first term and r is the common ratio
aₙ = 3.(4)^n-1
Comparing with the standard form:
1st term = 3
Common ratio = 4
