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3 years ago

9

60 POINTS HELPPPPP ASAP OR I FAIL 2. A fraction is a division problem in which the numerator is the dividend. What part of a div

ision problem is the denominator?

2 answers:

Anni [7]3 years ago

7 0

Answer:

Divisor

Step-by-step explanation:

Look at the picture*

77julia77 [94]3 years ago

4 0

Answer: The denominator is the bottom of the fraction in a division problem. For example if i have 1/2, the 2 would be my denominator. This is also your divisor. hope this helped

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I need major help pleaseeeeeeeeeeeeee

sveta [45]

Just make a triangle and an X and Y axis and reflect it over the Y axis. It's that simple. Then tell how you did it. Obviously it will be a reflection. Name the points (before and after) and you are done.

-Twix

4 0

3 years ago

The ratio of students who wear glasses to the total number of students in the class is 2:5 if there are 14 students who wear gla

vazorg [7]

Answer:

35 students in the class.

Step-by-step explanation:

If there are 5 students in the class, then 2 of them would wear glasses and 3 of them wouldn't. (Equation 1)

Now, there are 14 students how are wearing glasses.

We just times the whole Equation 1 by 7.

If there are 5 x 7 = 35 students in the class, then 2 x 7 = 14 of them would wear glasses and 3 x 7 = 21 of them wouldn't.

So, there are 35 students.

8 0

2 years ago

Find the solution of the square root of the quantity of x plus 2 plus 4 equals 8, and determine if it is an extraneous solution

Iteru [2.4K]

Consider the equation:

$\sqrt{x+2}+4 = 8$

Subtracting '4' from both the sides of the equation, we get as

$\sqrt{x+2}+4-4= 8-4$

$\sqrt{x+2}= 4$

Squaring on both the sides of the equation, we get

$(\sqrt{x+2})^2 = (4)^2$

$x+2 = 16$

Subtracting '2' from both the sides of the equation, we get

$x+2-2=16-2$

x=14

Since, An extraneous solution is a solution that arises from the solving process that is not really a solution at all. But, in this equation x=14 is the solution of the given equation.

Hence, it is not an extraneous solution.

4 0

3 years ago

Read 2 more answers

Three consecutive odd integers have a sum of 27. Find the integers.

jek_recluse [69]

$\sf \bf {\boxed {\mathbb {GIVEN:}}}$

Sum of three consecutive odd integers = $27$

$\sf \bf {\boxed {\mathbb {TO\:FIND:}}}$

The values of the three integers.

$\sf \bf {\boxed {\mathbb {SOLUTION:}}}$

$\sf\purple{The\:three\:consecutive \:odd\:integers\:are\:7,\:9\:and\:11.}$

$\sf \bf {\boxed {\mathbb {STEP-BY-STEP\:\:EXPLANATION:}}}$

Let us assume the three consecutive odd integers to be $x$ , $(x+2)$ and $(x+4)$ .

As per the condition, we have

$Sum \: \: of \: \: the \: \: three \: \: consecutive \: \: odd \: \: integers = 27$

$➺ \: x + (x + 2) + (x + 4) = 27$

$➺ \: x + x + 2 + x + 4 = 27$

Now, collect the like terms.

$➺ \: (x + x + x) + (2 + 4) = 27$

$➺ \: 3x + 6 = 27$

$➺ \: 3x = 27 - 6$

$➺ \: 3x = 21$

$➺ \: x = \frac{21}{3} \\$

$➺ \: x = 7$

Therefore, the three consecutive odd integers whose sum is $27$ are $\boxed{ 7 }$ , $\boxed{ 9 }$ and $\boxed{ 11 }$ respectively.

$\sf \bf {\boxed {\mathbb {TO\:VERIFY :}}}$

$⇢ 7 + 9 + 11 = 27$

$⇢ 27 = 27$

⇢ L. H. S. = R. H. S.

$\sf\blue{Hence\:verified.}$

$\red{\large\qquad \qquad \underline{ \pmb{{ \mathbb{ \maltese \: \: Mystique35ヅ}}}}}$

4 0

3 years ago

NEED HELP ASAP PLEASE WILL GIVE BRAINLYEST

AleksAgata [21]

Answer:

a) 1/2

b) 6/100

c)1/4

I'll explain how I got these answers later.

8 0

3 years ago

Read 2 more answers