1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
olga2289 [7]
3 years ago
9

60 POINTS HELPPPPP ASAP OR I FAIL 2. A fraction is a division problem in which the numerator is the dividend. What part of a div

ision problem is the denominator?

Mathematics
2 answers:
Anni [7]3 years ago
7 0

Answer:

Divisor

Step-by-step explanation:

Look at the picture*

77julia77 [94]3 years ago
4 0

Answer: The denominator is the bottom of the fraction in a division problem. For example if i have 1/2, the 2 would be my denominator. This is also your divisor. hope this helped

You might be interested in
M<5=? what’s it equal
WINSTONCH [101]

Answer:

<8

Step-by-step explanation:

They are the same angle degree.

5 0
3 years ago
JK and LM are perpendicular diameters of a circle. They are each 12 inches long. What is the approximate length of chord LK?
MA_775_DIABLO [31]

ANSWER:

I think the approximate length og chord Lk is around 8.5 inches long

3 0
3 years ago
What is the answer for <br> (x – 3)2 = 5
vodka [1.7K]

Answer:

x = 11/2 = 5.5

Step-by-step explanation:

2x-6 = 5

2x = 11

x = 11/2 = 5.5

7 0
2 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
3 years ago
If 3x^2-2x+7=0 then (x-1/3)^2=
Romashka-Z-Leto [24]
<span>3x^2−2x+7=0
</span>3x^2−2x+1/3+7−1/3=<span>0
</span><span>3<span>(x^2−2x/3+1/9)</span>+7−1/3=0
</span><span>3<span><span>(x−1/3)^</span>2</span>+(21−1)/3=0
</span><span>3<span><span>(<span>x−1/3</span>)^</span>2</span>=−<span>20/3
</span></span><span><span>(<span>x−<span>1/3</span></span>)^</span>2</span>=−<span>20/9</span>
5 0
3 years ago
Other questions:
  • Frame a linear equation in the form ax+by=c=0 by using the given of a,b,c a=-2,b=3,c=4
    7·1 answer
  • Given: circle k(O) with diameter AB and CD ⊥ AB<br><br> Prove: AD·CB=AC·CD
    10·1 answer
  • What is a parabola in a quadratic equation?
    13·1 answer
  • 12. The perimeter of a rectangle is 50 feet. The width is 5 less than the
    5·1 answer
  • Six times a number is ten plus four times a number
    10·1 answer
  • Somebody help please​
    8·2 answers
  • HELPPP MEE THANK U, 20 POINTS!~
    7·1 answer
  • PLEASE HELP DUDE I AM NOT SMART ENOUGH FOR THIS
    10·2 answers
  • What is 2x2 PLEASE ANSWER
    7·2 answers
  • I will give lots of points please help me
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!