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dezoksy [38]
3 years ago
6

G(x)=1/2(x-3)+1 find the inverse

Mathematics
1 answer:
Marysya12 [62]3 years ago
4 0

g(x)=\dfrac{1}{2}(x-3)+1\\\\y=\dfrac{1}{2}(x-3)+1\\\\\text{replace x with y and y with x}\\\\x=\dfrac{1}{2}(y-3)+1\\\\\text{solve for y}\\\\\dfrac{1}{2}(y-3)+1=x\ \ \ \ |-1\\\\\dfrac{1}{2}(y-3)=x-1\ \ \ \ |\cdot2\\\\y-3=2x-2\ \ \ \ |+3\\\\y=2x+1\\\\Answer:\ \boxed{g^{-1}(x)=2x+1}

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