Ask question

Ask question

All categories

3 years ago

9

To graph a rate or ratio from a table, how do you determine the scales to use on each axis?

1 answer:

Vadim26 [7]3 years ago

3 0

Determining the scale for the horizontal (x) axis. When making a graph, you want to use as much of the "graph paper" as possible, and generally, you want each <span>division or space on the graph to represent a whole number that makes the plotting relatively easy, such as 5, 10, 25, 50, 100, etc. </span>I hope my answer has come to your help. God bless and have a nice day ahead!

You might be interested in

The body of a person who weighs 50 kilograms contains around 2 × 10^2 grams of sodium chloride. How much sodium chloride is cont

Aleksandr [31]

Answer:

Answer is A. $3.6*10^{5}$

Step-by-step explanation:

Mass of Sodium Chloride in one 50kg person = $2*10^{2}$ grams

Mass of Sodium Chloride in $1.8*10^{3}$ 50kg people = $2*10^{2}$ * $1.8*10^{3}$

= $(1.8*10^{3})*(2*10^{2})$

= $3.6*10^{5}$

So the Answer is A.

8 0

4 years ago

INEQUALITIES-PLEASE HELP! Tricia receives a $5 allowance every week. She also earns $6.50 for every hour that she baby-sits. Nex

Zinaida [17]

Answer:

6.50x + 5 = 21.25 is the answer

Step-by-step explanation:

x=2.5

4 0

3 years ago

Help pleaseeeeeeeeee

harkovskaia [24]

97+x=27+64
x=27+64-97
x=-6

(Hopefully this is correct)

4 0

2 years ago

The side of a square is x, and the area is A. Express A in terms of x. Draw the graph which shows how A depends on x.

Alexandra [31]

a=x squared or x times itself

4 0

3 years ago

In Exercises 10 and 11, points B and D are points of tangency. Find the value(s) of x.<br>

Lemur [1.5K]

In both cases,

$AB^2=AD^2$

(as a consequence of the interesecting secant-tangent theorem)

So we have

10.

$(4x+7)^2=(6x-3)^2$

$16x^2+56x+49=36x^2-36x+9$

$20x^2-92x-40=0$

$5x^2-23x-10=0$

$(5x+2)(x-5)=0\implies\boxed{x=5}$

(omit the negative solution because that would make at least one of AB or AD have negative length)

11.

$(4x^2-18x-10)^2=(x^2+x+4)^2$

$16x^4-144x^3+244x^2+360x+100=x^4+2x^3+9x^2+8x+16$

$15x^4-146x^3+235x^2+352x+84=0$

$(x-7)(3x+2)(5x^2-17x-6)=0\implies\boxed{x=-\dfrac23\text{ or }x=7}$

(again, omit the solutions that would give a negative length for either AB or AD)

7 0

3 years ago