3 years ago

Need Help ASAP due by end of class on these math problem

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

3 0

It’s 3y not just 3. You need to add the exponent as well

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Write the sentence as an equation.<br> the quotient of t and 218 is equal to 156

Anvisha [2.4K]

Answer:

t/218 = 156

Step-by-step explanation:

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2 years ago

Line GJ is tangent to point A at point G.<br><br> If AG = 9 and GJ = 12, find AJ.

Artyom0805 [142]

Square root of 9^2+12^2

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3 years ago

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Find the missing value given (-1,7)(-3,d) m= 6 HELP ASAP WILL MAKE BRAINLEST

-Dominant- [34]

Answer:

d= -5

Step-by-step explanation:

The slope of a line is found by finding the ratio of change is y values to change is x values

$m=y_2-y_1/x_2-x_1$

The points on the line have coordinates at: (-1,7) (-3,d)

where ;

$y_2=d, y_1=7,x_2=-3,x_1=-1,m=6$

Applying the formula with values as;

$6=\frac{d-7}{-3--1} \\\\6=\frac{d-7}{-3+1} \\\\6=\frac{d-7}{-2} \\\\6*-2=d-7\\\\-12=d-7\\\\-12+7=d\\\\-5=d$

The value of d = -5

The coordinates of the points (-1,7) (-3,-5)

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3 years ago

Is n+4 equal to 8(n - 4)

weqwewe [10]

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3 years ago

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Use Newton's method with initial approximation x1 = −2 to find x2, the second approximation to the root of the equation x3 + x +

nevsk [136]

Answer:

$x_2 \approx -1.769$

Step-by-step explanation:

Let $f(x)=x^3+x+7$

So $f'(x)=3x^2+1$

$x_{n+1}=x_n-\frac{f(x_n)}{f'(x_n)}$

Let $x_1=-2$

We are going to find $x_2$

So we are evaluating $-2-\frac{f(-2)}{f'(-2)}$

First step find f(-2)

Second step find f'(-2)

Third step plug in those values and apply PEMDAS!

$f(-2)=(-2)^3+(-2)+7=-8-2+7=-10+7=-3$

$f'(-2)=3(-2)^2+1=3(4)+1=12+1=13$

$x_2=-2-\frac{-3}{13} \\\\ x_2=\frac{-26+3}{13} \\\\ x_2=\frac{-23}{13} \\\\ x_2 \approx -1.769$

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2 years ago