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2 years ago

11

the clemson football team gained 8 yards on their first play, lost 13 yards on the second and lost an additional 2 yards on the

third play. at the beginning of the fourth play, how far were they from the starting point?

1 answer:

myrzilka [38]2 years ago

6 0

7 yards away from the starting point

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Last year, there were 12,000 students at a local college. There were 2000 more female students than male students. How many male

krek1111 [17]

There is 7,000 female students, and 5,000 male students. Because, if there was 2,000 more female students then male, you have to find out what two numbers add up to 12,000. (Tip, to make it easier, take away the thousands, like 7+5)

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3 years ago

Let f(x)=3x+5 and g(x)=x^2 find (f-g)(x)

dlinn [17]

Answer:

(f - g)(x) = -x² + 3x + 5

General Formulas and Concepts:

<u>Pre-Algebra</u>

Equality Properties

<u>Algebra I</u>

Function Notation
Combining Like Terms

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x + 5

g(x) = x²

(f - g)(x) is f(x) - g(x)

<u>Step 2: Find (f - g)(x)</u>

Substitute: (f - g)(x) = 3x + 5 - x²
Rewrite: (f - g)(x) = -x² + 3x + 5

7 0

2 years ago

A quadratic equation is shown below:

sweet [91]

Answer:

Part A:

( 1.8333, -0.08333)

Part B:

x = 2 or x = 5/3

Step-by-step explanation:

The quadratic equation

$3x^{2}-11x+10=0$ has been given.

Part A:

We are required to determine the vertex. The vertex is simply the turning point of the quadratic function. We shall differentiate the given quadratic function and set the result to 0 in order to obtain the co-ordinates of its vertex.

$\frac{d}{dx}(3x^{2}-11x+10)=6x-11$

Setting the derivative to 0;

6x - 11 = 0

6x = 11

x = 11/6

The corresponding y value is determined by substituting x = 11/6 into the original equation;

y = 3(11/6)^2 - 11(11/6) + 10

y = -0.08333

The vertex is thus located at the point;

( 1.8333, -0.08333)

Find the attached

Part B:

We can use the quadratic formula to solve for x as follows;

The quadratic formula is given as,

$x=\frac{-b+/-\sqrt{b^{2}-4ac } }{2a}$

From the quadratic equation given;

a = 3, b = -11, c = 10

We substitute these values into the above formula and simplify to determine the value of x;

$x=\frac{11+/-\sqrt{11^{2}-4(3)(10) } }{2(3)}=\frac{11+/-\sqrt{1} }{6}\\\\x=\frac{11+/-1}{6}\\\\x=\frac{11+1}{6}=2\\\\x=\frac{11-1}{6}=\frac{5}{3}$

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3 years ago

What is the radical equivalent for 197^7/8?

tensa zangetsu [6.8K]

Answer:

$\sqrt[8]{197^{7} }$

Step-by-step explanation:

$\sqrt[8]{197^{7} }$

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2 years ago

What is the range of 2 4 2 6 1

sashaice [31]

4 6-2 = 4 you subtract the largest and smallest number to get the answer

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2 years ago

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