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3 years ago

Assume that we want to construct a confidence interval. Do one of the following, as appropriate:

Mathematics

1 answer:

zhannawk [14.2K]3 years ago

3 0

Answer: Option 'a' is correct.

Step-by-step explanation:

To construct a confidence interval, we have four steps to do:

1) Recognise the sample statistic by calculating the sample mean and sample variance.

2) Recognise the confidence level i.e. 90%, 95% etc.

3) Calculate the margin of error :

As we know that Margin of error = Critical value × Standard deviation

Now, critical value in case of t - test,

$t_{\frac{\alpha}{2},v}$

4) find the confidence interval which is given below:

Confidence interval = Margin of error + Sample statistics

So, Option 'a' is correct.

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2 years ago

What is the value of the expression x + (–y) when x = –2.3 and y = –5.9? A. –8.2 B. –3.6 C. 3.6 D. 8.2

11Alexandr11 [23.1K]

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2 years ago

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2 years ago

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Alexxx [7]

When you have 3 choices for each of 6 spins, the number of possible "words" is
3^6 = 729

The number of permutations of 6 things that are 3 groups of 2 is
6!/(2!×2!×2!) = 720/8 = 90

A) The probability of a word containing two of each of the letters is 90/729 = 10/81

The number of permutations of 6 things from two groups of different sizes is
(2 and 4) : 6!/(2!×4!) = 15
(3 and 3) : 6!/(3!×3!) = 20
(4 and 2) : 15
(5 and 1) : 6
(6 and 0) : 1

B) The number of ways there can be at least 2 "a"s and no "b"s is
15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.

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These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.

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2 years ago

Assume that we want to construct a confidence interval. Do one of the​ following, as​ appropriate:

Assume that we want to construct a confidence interval. Do one of the following, as appropriate: