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2 years ago

Assume that we want to construct a confidence interval. Do one of the following, as appropriate:

Mathematics

1 answer:

zhannawk [14.2K]2 years ago

3 0

Answer: Option 'a' is correct.

Step-by-step explanation:

To construct a confidence interval, we have four steps to do:

1) Recognise the sample statistic by calculating the sample mean and sample variance.

2) Recognise the confidence level i.e. 90%, 95% etc.

3) Calculate the margin of error :

As we know that Margin of error = Critical value × Standard deviation

Now, critical value in case of t - test,

$t_{\frac{\alpha}{2},v}$

4) find the confidence interval which is given below:

Confidence interval = Margin of error + Sample statistics

So, Option 'a' is correct.

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2 years ago

Select the correct answer

Paladinen [302]

Answer:

a) We get $\mathbf{A+B=x^2-2x+1}$

So, Is the result of A+B is a polynomial:Yes

b) We get $\mathbf{A-B=6x^3-7x^2+2x-1}$

So, Is the result of A-B is a polynomial:Yes

c) We get $\mathbf{A.B=9x^6+21x^5-18x^4+9x^3-3x^2}$

So, Is the result of A.B is a polynomial:Yes

Step-by-step explanation:

We are giving the polynomial equations:

$A= 3x^2(x-1)\\B=-3x^3+4x^2-2x+1$

We need to find

a) A+B

$A+B=3x^2(x-1)+(-3x^3+4x^2-2x+1)\\A+B=3x^3-3x^2-3x^3+4x^2-2x+1\\A+B=3x^3-3x^3-3x^2+4x^2-2x+1\\A+B=x^2-2x+1\\$

So, we get $\mathbf{A+B=x^2-2x+1}$

So, Is the result of A+B is a polynomial:Yes

b) A-B

$A-B=3x^2(x-1)-(-3x^3+4x^2-2x+1)\\A-B=3x^3-3x^2+3x^3-4x^2+2x-1\\A-B=3x^3+3x^3-3x^2-4x^2+2x-1\\A-B=6x^3-7x^2+2x-1\\$

So, we get $\mathbf{A-B=6x^3-7x^2+2x-1}$

So, Is the result of A-B is a polynomial:Yes

c) A . B

$A.B=3x^3(-3x^3+4x^2-2x+1)-3x^2(-3x^3+4x^2-2x+1)\\A.B=9x^6+12x^5-6x^4+3x^3+9x^5-12x^4+6x^3-3x^2\\A.B=9x^6+12x^5+9x^5-6x^4-12x^4+3x^3+6x^3-3x^2\\A.B=9x^6+21x^5-18x^4+9x^3-3x^2$

So, we get $\mathbf{A.B=9x^6+21x^5-18x^4+9x^3-3x^2}$

So, Is the result of A.B is a polynomial:Yes

7 0

2 years ago

The rectangle below has an area of x^2-x-72x 2 ?x?72 square meters and a length of x+8x+8 meters. What expression represents the

Varvara68 [4.7K]

Answer:

Area of the rectangle is given by:

$A = l \times w$

where

A is the area of the rectangle

l is the length of the rectangle

w is the width of the rectangle respectively.

As per the given statement:

Area of the rectangle(A) = $x^2-x-72$ square meters

length of the rectangle(l) = x+8

Substitute these in the given formula we have;

$x^2-x-72 = (x+8) \times w$

$x^2-9x+8x-72 = (x+8) \times w$

$x(x-9)+8(x-9)= (x+8) \times w$

$(x+8)(x-9)= (x+8) \times w$

Divide both sides by x+8 we have;

$w = (x-9)$ meters.

Therefore, the expression represents the width of the rectangle is x-9 meters

4 0

3 years ago

Assume that we want to construct a confidence interval. Do one of the​ following, as​ appropriate:

Assume that we want to construct a confidence interval. Do one of the following, as appropriate: