Answer:
Step-by-step explanation:
y=a(x-0)(x-2)
=a(x^2-2x)
=a(x^2-2x+1-1)
or y=a(x-1)^2-a
(1,5) lies on it.
5=a(1-1)^2-a
5=0-a
or a=-5
so y=-5(x-1)^2+5
<span>Because the four numbers are consecutive, we can call the first one x, and the other three are x+1, x+2, and x+3, respectively.
x * (x+1) = (x+2) * (x+3) - 38
x^2 + x = x^2 + 5x +6-38
x^2 + x = x^2 + 5x - 32
-4x = -32
x=8
The four numbers are 8, 9, 10, and 11
check solution: 8*9=10*11-38
72=110-38
72=72</span>
Answer:
f(4) = -8
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = -x - 4
f(4) is x = 4
<u>Step 2: Evaluate</u>
- Substitute in <em>x</em>: f(4) = -4 - 4
- Subtract: f(4) = -8
-17 is the correct answer:)
