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liberstina [14]
3 years ago
10

Mr.Evans is paid $9.20 per hour for the first 40 hours he works in a week.He is paid 1.5 times that rate for each hour after tha

t.Last week,Mr.Evans worked 42.25 hours.He says he earned $388.70 last week.Do you agree?
Mathematics
1 answer:
yKpoI14uk [10]3 years ago
8 0

Answer:

I do not agree.  If Mr. Evans worked 42.25 at a rate of $9.20 per hour for the first 40 hours and 1.5 times that rate after, he would have made a total of $399.05.  

Step-by-step explanation:

In order to find the total amount that Mr. Evans would have earned last week, we need to first calculate how much he earned in his regular pay at 40 hours.  For up to 40 hours, Mr. Evans makes $9.20 per hour, so his total wages earned after 40 hours is:  40 x 9.2 = $368.00.  However, Mr. Evans also worked 2.25 hours of overtime at a rate of 1.5 times $9.20 or 9.2 x 1.5 = $13.80.  At $13.80 for 2.25 hours, Mr. Evans would earn:  13.80 x 2.25 = $31.05.  When you add his base pay of $368.00 plus his over time pay of $31.05, you get a total of $399.05.

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4/25+1/5 in simplest form
Evgen [1.6K]
It would be 9/25. First you find the common denominator which is 25 so then you convert 1/5 to 5/25 so now you have 4/25+5/25 which you would get 9/25 and since 9 can only be divided be 3 and 25 can't your answer would be 9/25.
3 0
4 years ago
(-4,5) and (4,0) find the distance between each pair of points
aleksklad [387]

Answer:

9.4339 units

Step-by-step explanation:

Here we are given with two coordinates and asked to determine the distance between them.

Here we are going to use the distance formula, which is given as under

D=\sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Where

(x_1,y_1) = (-4,5)

(x_2,y_2) = (4,0)

Replacing these values in the distance formula

D =\sqrt{(-4-4))^2+(5-0)^2}

D =\sqrt{(-8)^2+(5)^2}

D =\sqrt{64+25}

D =\sqrt{89}

D= 9.4339

Hence the distance is 9.4339 units

6 0
3 years ago
WILL MARK BRAINLIEST!!!
Juliette [100K]
Volume  = area of base * height  =  pi r^2 h

D is correct
7 0
3 years ago
Read 2 more answers
Solve the equation for Imaginary Numbers 1/2(x^2+40)=-12
Nimfa-mama [501]

Answer:

8i and -8i

Step-by-step explanation:

Move everything into the left-hand side to get a quadratic equation:

\frac{1}{2}(x^2+40)=-12\\\frac{1}{2}x^2+20=-12\\\frac{1}{2}x^2+32=0

Solve for x using the quadratic formula:

\frac{1}{2}x^2+32=0\\x=\frac{-b\±\sqrt{b^2-4ac}}{2a}\\x=\frac{-(0)\±\sqrt{0^2-4(\frac{1}{2})32}}{2(\frac{1}{2})}\\x=\±\sqrt{-64}\\x=\±8i

The two imaginary solutions for the equation are 8i and -8i.

3 0
3 years ago
What is the exact distance from (−1, 4) to (6, −2)? square root of 80. units square root of 82. units square root of 85. units s
Roman55 [17]

Answer:

\sqrt{85}.

Step-by-step explanation:

x-coordinates:

  • First point: -1.
  • Second point: 6.
  • Difference: |-1 - 6| = |-7| = 7.

y-coordinates:

  • First point: 4.
  • Second point: -2.
  • Difference: |4 - (-2)| = |6| = 6.

Refer to the diagram attached. Consider these two points as the two end points of the hypotenuse of a right triangle. The lengths of the two legs are equal to:

  • the difference between the two x-coordinates, 7, and
  • the difference between the two y-coordinates, 6.

Apply Pythagorean Theorem to find the length of the hypotenuse (which is equal to the distance between the two points in question.)

\begin{aligned}\text{Hypotenuse} &= \sqrt{(\text{First Leg})^2 + (\text{Second Leg})^2} \\ &= \sqrt{7^2 + 6^2} \\ &= \sqrt{85}\end{aligned}.

8 0
3 years ago
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