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gtnhenbr [62]
3 years ago
5

What is the slope of this line?

Mathematics
1 answer:
statuscvo [17]3 years ago
4 0
(0,6) and (8,8)
slope = (8-6)/(8-0) = 2/8 = 1/4

answer
1/4
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Which statements are correct? Check all that apply. The total number of students is < 160. The total number of students is &g
dusya [7]

Answer:

The percent as a part to whole ratio is Start Fraction 10 over 100 end fraction

The percent as a part to whole ratio is start fraction 160 over 100 end fraction.

There are 250 students in the school

Step-by-step explanation:

In the Juniour park school there are 160 students and out of these only 10 percent students play musical instruments. The fraction are start with 10 and end 100 is the correct. The ration of the students playing the musical instruments is 10 percents.

3 0
3 years ago
Read 2 more answers
The graph below shows a quadratic function f(x) and an absolute value function g(x)
Sophie [7]

Answer:

The x-values that are approximate solution of the equation f(x) = g(x) are x_{1} \approx -3.5 and x_{2}\approx 5, respectively.

Step-by-step explanation:

From graph we infer that the x-values that represents a solution to the system of equations corresponds to those values of x in which both functions coincide. As we see, there are two x-values for f(x) = g(x), which are described below:

x_{1} \approx -3.5 and x_{2}\approx 5

The x-values that are approximate solution of the equation f(x) = g(x) are x_{1} \approx -3.5 and x_{2}\approx 5, respectively.

6 0
3 years ago
What is the slope of the function below?<br> y=3x+5 please help!!!
ladessa [460]
X=-5/3 it’s a fraction
8 0
2 years ago
How to find the inverse of a function
Studentka2010 [4]
Switch the x and the y and solve for y 
eg inverse of 2y= 3x+1
swith x and y
2x=3y+1
now solve for y
y =(2x-1)/3
5 0
3 years ago
How do you solve this?
solong [7]

It looks like your equations are

7M - 2t = -30

5t - 12M = 115

<u>Solving by substitution</u>

Solve either equation for one variable. For example,

7M - 2t = -30   ⇒   t = (7M + 30)/2

Substitute this into the other equation and solve for M.

5 × (7M + 30)/2 - 12M = 115

5 (7M + 30) - 24M = 230

35M + 150 - 24M = 230

11M = 80

M = 80/11

Now solve for t.

t = (7 × (80/11) + 30)/2

t = (560/11 + 30)/2

t = (890/11)/2

t = 445/11

<u>Solving by elimination</u>

Multiply both equations by an appropriate factor to make the coefficients of one of the variables sum to zero. For example,

7M - 2t = -30   ⇒   -10t + 35M = -150 … (multiply by 5)

5t - 12M = 115   ⇒   10t - 24M = 230 … (multiply by 2)

Now combining the equations eliminates the t terms, and

(-10t + 35M) + (10t - 24M) = -150 + 230

11M = 80

M = 80/11

It follows that

7 × (80/11) - 2t = -30

560/11 - 2t = -30

2t = 890/11

t = 445/11

4 0
2 years ago
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