All categories

2 years ago

The measure of an angle is 28° greater than its complement. Find the measure of each angle.

Mathematics

1 answer:

artcher [175]2 years ago

7 0

The measures of each angle are:
59 and 31
59 + 31 = 90
59 - 31 = 28

You might be interested in

Please tell me the what to do with this problem

frez [133]

Because the prices are different, you need to use two variables, one for each price.

Let the price for the plain one be X and the price for the printed one be Y.

You would multiply the number of each shirt by the variable:

3 plain would be 3X and 2 printed would be 2Y.

You then need to add those together to get the total cost:

Total cost = 3X + 2Y

7 0

3 years ago

Read 2 more answers

An 8 foot piece of cotton cloth costs $ 3.84. What is the price per inch?

aleksklad [387]

Answer:

0.43

Step-by-step explanation:

3.84/8= 0.43

4 0

2 years ago

Read 2 more answers

What is the value of x?

Angelina_Jolie [31]

Answer:

x = 5.4

Step-by-step explanation:

3/x = 4/7.2

cross-multiply:

4x = 21.6

x = 5.4

5 0

3 years ago

A juice company produces 8,064 cartons of juice in 21 days. Each day, they produced the same number of cartons and delivered tho

KatRina [158]

8064 cartons in 21 days......8064/21 = 384 cartons per day

the cartons were delivered in cases of 6.....384 / 6 = 64 cases

each of 16 coffee shops received an equal number of cases..
64/16 = 4.....so each coffee shop received 4 cases per day <==

7 0

2 years ago

Read 2 more answers

Find the equation, (f(x) = a(x - h)2 + k), for a parabola containing point (2, -1) and having (4, -3) as a vertex. What is the s

Nataliya [291]

Answer:

$f(x)=\frac{1}{2}x^2-4x+5$

Step-by-step explanation:

A parabola is written in the form

$f(x)=a((x-h)^2+k)$ (1)

where:

$h$ is the x-coordinate of the vertex of the parabola

$ak$ is the y-coordinate of the vertex of the parabola

$a$ is a scale factor

For the parabola in the problem, we know that the vertex has coordinates (4,-3), so we have:

$h=4$ (2)

$ak=-3$

From this last equation, we get that $a=\frac{-3}{k}$ (3)

Substituting (2) and (3) into (1) we get the new expression:

$f(x)=-\frac{3}{k}((x-4)^2+k) = -\frac{3}{k}(x-4)^2 -3$ (4)

We also know that the parabola contains the point (2,-1), so we can substitute

x = 2

f(x) = -1

Into eq.(4) and find the value of k:

$-1=-\frac{3}{k}(2-4)^2-3\\-1=-\frac{3}{k}\cdot 4 -3\\2=-\frac{12}{k}\\k=-\frac{12}{2}=-6$

So we also get:

$a=-\frac{3}{k}=-\frac{3}{-6}=\frac{1}{2}$

So the equation of the parabola is:

$f(x)=\frac{1}{2}((x-4)^2 -6)$ (5)

Now we want to rewrite it in the standard form, i.e. in the form

$f(x)=ax^2+bx+c$

To do that, we simply rewrite (5) expliciting the various terms, we find:

$f(x)=\frac{1}{2}((x^2-8x+16)-6)=\frac{1}{2}(x^2-8x+10)=\frac{1}{2}x^2-4x+5$

6 0

3 years ago