Consider the quadratic function f(x) = 2x2 – 8x – 10. The x-component of the vertex is . The y-component of the vertex is . The

Question

telo118 [61]

2 years ago

15

Consider the quadratic function f(x) = 2x2 – 8x – 10. The x-component of the vertex is . The y-component of the vertex is . The

discriminant is b2 – 4ac = (–8)2 – (4)(2)(–10) =

Mathematics

2 answers:

mr_godi [17] · Answer 1 · 2022-05-28T02:59:52+03:00

F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x = 2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144

12345 [234] · Answer 2 · 2022-05-28T05:08:20+03:00

12345 [234]2 years ago

4 0

Answer:

1. 2

2. -18

3. 144