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velikii [3]
3 years ago
9

What is the correct answer to the math problem 20+30×0+1

Mathematics
2 answers:
Bumek [7]3 years ago
6 0
21
is what I got on my calculator
Alexeev081 [22]3 years ago
5 0
The answer is 21 because of PEMDAS
20+30x0+1 
30x0=0 and you still have 20+1
and 20 +1 =21
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*20 POINTS*
Paraphin [41]

Answer:

If you want to use the Rational Zeros Theorem, as instructed, you need to use synthetic division to find zeros until you get a quadratic remainder.

P: ±1, ±2, ±3, ±6  (all prime factors of constant term)

Q: ±1, ±7              (all prime factors of the leading coefficient)

P/Q: ±1, ±2, ±3, ±6, ±1/7, ±2/7, ±3/7, ±6/7  (all possible values of P/Q)

Now, start testing your values of P/Q in your polynomial:

f(x)=7x4-9x3-41x2+13x+6

You can tell f(1) and f(-1) are not zeros since they're not = 0Now try f(2) and f(-2):

f(2)=7(16)-9(8)-41(4)+13(2)+6

       112-72-164+26+6 ≠ 0

f(-2)=7(16)-9(-8)-41(4)+13(-2)+6

       112+72-164-26+6 = 0  OK!! There is a zero at x=-2

This means (x+2) is a factor of the polynomial.

Now, do synthetic division to find the polynomial that results from

(7x4-9x3-41x2+13x+6)÷(x+2):

-2⊥ 7   -9   -41    13     6

         -14   46   -10    -6          

      7  -23   5       3     0     The remainder is 0, as expected

The quotient is a polynomial of degree 3:

7x3-23x2+5x+3

Now, continue testing the P/Q values with this new polynomial.  Try f(3):

f(3)=7(27)-23(9)+5(3)+3

      189-207+15+3 = 0  OK!!  we found another zero at x=3

Now, another synthetic division:

3⊥ 7   -23    5     3

          21   -6   -3_

    7    -2    -1    0  

The quotient is a quadratic polynomial:

7x2-2x-1  This is not factorable, you need to apply the quadratic formula to find the 3rd and 4th zeros:

x= (1±2√2)÷7

The polynomial has 4 zeros at x=-2, 3, (1±2√2)÷7

Step-by-step explanation:

7 0
3 years ago
What is the answer to this problem?
yarga [219]
Try this:
V=a³=6.2³=238,328 in.³
Answer: A.
3 0
3 years ago
5 Points
Simora [160]

Answer: the answer is indeed (4,8)

Step-by-step explanation:

4 0
3 years ago
How to solve: dy/dx=e^(x-y), y(0)=ln3
ella [17]
Hello,

\dfrac{dy}{dx} = \dfrac{e^x}{e^y} \\

e^y*dy=e^x*dx \\

e^y=e^x+C\\

if\ x=0\ then\ y=ln(3) ==\ \textgreater \  3=1+C==\ \textgreater \ C=2\\

\boxed{y=ln(2+e^x)}\\


8 0
3 years ago
Read 2 more answers
For a school project, Sarah plans to build a scale model of an Egyptian pyramid. She will be using a scale of: 1 cm = 5 meters.
Vinvika [58]

Answer:

B

Step-by-step explanation:

you divide 140 by 5 so 28 is the answer

3 0
3 years ago
Read 2 more answers
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