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sleet_krkn [62]

3 years ago

13

What is the standard equation of the circle in the diagram? ^

1 answer:

den301095 [7]3 years ago

5 0

Answer:

$(x - 3)^{2} + (y + 4)^{2} = 4$

Step-by-step explanation:

Center is at (3, -4) and the radius is 2

$(x - 3)^{2} + (y + 4)^{2} = 4$

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Which points on the number line represent the quotients of these expressions? 12 divided by -6 and -15 divided by -3

yaroslaw [1]

Answer:

2,5

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3 years ago

(4 x 5)2 - 6 + 3 =<br> (Hint: it’s not 37)

xxTIMURxx [149]

Answer:

37

Step-by-step explanation:

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3 years ago

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Are 4 and 9 relatively prime?

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nbvStep-by-step explanation:

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3 years ago

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in a AP the first term is 8,nth term is 33 and sum to first n terms is 123.Find n and common difference

allsm [11]

I believe there is no such AP...

Recursively, this sequence is supposed to be given by

$\begin{cases}a_1=8\\a_k=a_{k-1}+d&\text{for }k>1\end{cases}$

so that

$a_k=a_{k-1}+d=a_{k-2}+2d=\cdots=a_1+(k-1)d$

$a_n=a_1+(n-1)d$

$33=8+(n-1)d$

$21=(n-1)d$

$n$ has to be an integer, which means there are 4 possible cases.

Case 1: $n-1=1$ and $d=21$ . But

$\displaystyle\sum_{k=1}^2(8+21(k-1))=37\neq123$

Case 2: $n-1=21$ and $d=1$ . But

$\displaystyle\sum_{k=1}^{22}(8+1(k-1))=407\neq123$

Case 3: $n-1=3$ and $d=7$ . But

$\displaystyle\sum_{k=1}^4(8+7(k-1))=74\neq123$

Case 4: $n-1=7$ and $d=3$ . But

$\displaystyle\sum_{k=1}^8(8+3(k-1))=148\neq123$

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3 years ago

Tikiro places a wrench on a nut and applies a downward force of 32 pounds to tighten the nut. If the center of the nut is at the

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Answer:

Answer: b. 20.8 ft-lb

Step-by-step explanation:

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3 years ago