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3 years ago

HELP PLEASE.................

Mathematics

1 answer:

Kryger [21]3 years ago

6 0

Zero

There is no solution for these equations as there is no even one point of intersection between them

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Write an equation for the description<br> The sum of 13 and a number x is equal to 15.

mote1985 [20]

I think it’s 13+x=15

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3 years ago

Are the inequalities c+3> 5 and c-1>1 equivalent? Explain.

Kaylis [27]

Answer:

yes

Step-by-step explanation:

c + 3 > 5

subtract 3 from both sides: c > 2

c - 1 > 1

Add 1 to both sides: c > 2

Therefore, they are equivalent.

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3 years ago

Find the product of -5 1/3 • 4 2/5

fomenos

Answer:

Simplify the expression.

Exact Form: -352/15

Decimal Form: -23.46

Mixed Number Form: -23 7/15

Step-by-step explanation:

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3 years ago

Simplify the expression

Reil [10]

Answer:453rft

Step-by-step explanation:

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3 years ago

Read 2 more answers

Write a quadratic equation in standard form that has a vertex of (-2, 6) and passes through (-4, -2).

Marizza181 [45]

Answer:

The equation of the quadratic in standard form is:

$y=-2x^2-8x-2$

Step-by-step explanation:

Since they give us the information about where the vertex of the parabola is located, and one extra points where it passes through, we can use the general form of a quadratic in vertex form:

$y-y_v=a\,(x-x_v)^2$

where $(x_v,y_v)$ is the location of the vertex (in our case the point (-2,6).

Therefore the equation above becomes:

$y-y_v=a\,(x-x_v)^2\\y-6=a\,(x-(-2))^2\\y-6=a\,(x+2)^2$

Now,we can use the fact that the point (-4,-2) is also a point of the graph, to find the value of the parameter $"a"$ :

$y-6=a\,(x+2)^2\\-2-6=a\,(-4+2)^2\\-8=a\,(-2)^2\\-8=a\,*4\\a=-2$

Then, the equation of the quadratic with such characteristics becomes:

$y-6=-2\,(x+2)^2\\y-6=-2x^2-8x-8\\y=-2x^2-8x-2$

which is the equation of the quadratic in standard form.

7 0

3 years ago