(a) We have ⌊<em>x</em>⌋ = 5 if 5 ≤ <em>x</em> < 6, and similarly ⌊<em>x</em>/3⌋ = 5 if
5 ≤ <em>x</em>/3 < 6 ==> 15 ≤ <em>x</em> < 18
(b) ⌊<em>x</em>⌋ = -2 if -2 ≤ <em>x</em> < -1, so ⌊<em>x</em>/3⌋ = -2 if
-2 ≤ <em>x</em>/3 < -1 ==> -6 ≤ <em>x</em> < -3
In general, ⌊<em>x</em>⌋ = <em>n</em> if <em>n</em> ≤ <em>x</em> < <em>n</em> + 1, where <em>n</em> is any integer.
I do not understand what is being asked in (c) and (d), so you'll have to clarify...
Answer: We can find out the missing statement with help of below explanation.
Step-by-step explanation:
We have a rectangle ABCD with diagonals AC and BD ( shown in given figure.)
We have to prove: Diagonals AC and BD bisect each other.
In triangles, AED and BEC.
( By alternative angle theorem)
( Because ABCD is a rectangle)
( By alternative angle theorem)
By ASA postulate,
By CPCTC, 
and 
⇒ BE= ED and CE=EA
By the definition of bisector, AC and BD bisect each other.
Answer:
2,535
Step-by-step explanation:
X = 8
Y = 2 Your welcomeeeeee
Answer:
False. They will be parallel to each other
