Answer:
The probability that they sit next to each other is 50%.
Step-by-step explanation:
Consider the provided information.
It is given that there are four seats within the row are first come, first served during boarding.
There are 4 seats and 2 customers (Karen and Georgia)
The total number of ways in which Karen and Georgia can sit is: 
Now if they will sit together, then consider Karen and Georgia as a single unit.
Thus, the number of ways in which they can sit together is: 
The required probability is:

Hence, the probability that they sit next to each other is 50%.
The number of new calculators tested was 50 . . . 8 were bad and 42 were good.
The ratio of defective ones to new ones tested is 8:50 or 4:25 or 16% .
Answer:
I've been trying to figure this out with out a chart and i keep confusing myself
Step-by-step explanation:
nothing
Answer:
c
Step-by-step explanation:
Given that:

since cos (kπ) = 
Then, the series can be expressed as:

In the sum of an alternating series, the best bound on the remainder for the approximation is related to its
term.
∴



