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Illusion [34]
3 years ago
8

Expand (- 3a - 5x) (- 2b - 4y).​

Mathematics
2 answers:
vekshin13 years ago
8 0

Answer:  −3a(−2b−4y).−5x(−2b−4y). to this  

6ab+12ay+10bx+20xy

Step-by-step explanation: hope this helps :)

Studentka2010 [4]3 years ago
4 0

Answer:

( −3a − 5x ) ( −2b − 4y )

= ( −3a + − 5x ) ( −2b + −4y )

=( −3a ) ( −2b ) + ( −3a ) ( −4y ) + ( −5x ) ( − 2b ) + ( − 5x ) ( − 4y )

= 6ab + 12ay + 10bx + 20xy

Hope it helps

Please mark me as the brainliest

Thank you

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A man goes 10m due east and 24m due north find the distance from the starting(pls help )
Mandarinka [93]

Answer:

26m

Step-by-step explanation:

10^2+24^2=26^2

7 0
3 years ago
Can you solve the equation 2/3(4x - 5)= 8 by using the division property of equality? explain.
bija089 [108]

\dfrac{2}{3}(4x-5)=8\qquad|\text{use the division property of equality}\\\\\dfrac{2}{3}(4x-5):\dfrac{2}{3}=8:\dfrac{2}{3}\\\\\dfrac{2}{3}(4x-5)\cdot\dfrac{3}{2}=8\cdot\dfrac{3}{2}\\\\4x-5=4\cdot3\\\\4x-5=12\qquad|\text{use addition property of equality}\\\\4x-5+5=12+5\\\\4x=17\qquad|\text{use the division property of equality}\\\\4x : 4=17:4\\\\x=\dfrac{17}{4}

8 0
3 years ago
The function f(x) = −x^2 − 5x + 50 shows the relationship between the vertical distance of a diver from a pool's surface f(x), i
pychu [463]
Set the function to equal zero:

-x^2 - 5x + 50 = 0

To find the zeros, or solutions, to this problem, we will use the quadratic formula:

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

Plug the values into the equation:

a = -1, b = -5, c = 50

x=\frac{5\pm\sqrt{-5^2-4(-1)(50)}}{2(-1)}

x=\frac{5\pm\sqrt{25+200}}{-2}

x=\frac{5\pm15}{-2}

Solve for both plus and minus:

\frac{5 + 15}{-2} = \frac{20}{-2} = -10

\frac{5 - 15}{-2} = \frac{-10}{-2} = 5

x = -10, x = 5

The question cannot use a negative value for x, as the diver cannot dive a negative distance from the board.

The answer is '<span>x = 5; the diver hits the water 5 feet away horizontally from the board', because x represents the horizontal distance away from the board.</span>
4 0
3 years ago
Can someone please answer this and explain how you got it? Or just show your work for it please and thank u &lt;3
serg [7]

Answer:

please mark me as brainlist please

Step-by-step explanation:

we know, ∠BGA = 90

In right angled triangle BGA

AB = 12 cm (diameter of circle)

⇒ (AB)2 = (AG)2 + (BG)2

⇒ 122 = 82 + (BG)2

⇒ BG = 4√5

In right angled triangle BCG

Let CG be x cm.

⇒ (BC)2 = (CG)2 + (BG)2

⇒ (BC)2 = x2 + (4√5)2 ----(1)

As we know,

⇒ (BC)2 = CG × CA ----(2)

From equation (1) and equation (2)

⇒ x2 + (4√5)2 = x × (x + 8)

⇒ x2 + (4√5)2 = x2 + 8x

⇒ 8x = 80

⇒ x = 10 cm

From equation (2)

⇒ (BC)2 = CG × CA

⇒ (BC)2 = 10 × 18 = 180

⇒ BC = √180 = 6√5

6 × 5 = 30

5 0
2 years ago
PLEASE PLEASE PLEASE PLEASE PLEASE HELP <br><br><br> If sin B= 0.5678, what is the measure of
Jlenok [28]

Answer:

sin B= 0.5678,

B=sin-¹(0.5678,)

B=34.59°

3 0
3 years ago
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