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3 years ago

What is the value of x? x/4-5=6

2 answers:

5 0

Step by step:
Step 1: add 5 to both sides which would give you x/4=11
Step 2: multiply both sides by 4 (to get 4 out of the denominator) which gives you x=11(4)
Step 3: Simplify giving you the answer x=44

ivann1987 [24]3 years ago

3 0

Let's solve your equation step-by-step.x(4)−5=6Step 1: Simplify both sides of the equation.x(4)−5=6Simplify: (Show steps)4x−5=6Step 2: Add 5 to both sides.4x−5+5=6+54x=11Step 3: Divide both sides by 4.4x4=114x=114Answer:x=114

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A circular mirror has a circumference of 30 pi inches. What is the area of mirror?

Aleonysh [2.5K]

Answer:

Step-by-step explanation:

circumference = 2πr

2πr = 30π inches

$r=\frac{30\pi}{2\pi}=15in$

Area = πr² = π*15*15 = 225π square inches

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3 years ago

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2 years ago

in a triangle TRY measure angle R is 3 times measure angle T and measure angle Y is 15 more than measure angle T find the measur

r-ruslan [8.4K]

Answer:

Angle R is 99 degree

Angle Y=48 degrees

Angle T is 33 degrees

Step-by-step explanation:

Let angle T be x

Angle R will be 3x

Angle Y will be x+15

Total=x+3x+x+15=5x+15

5x+15=180

5x=165

x=165/5=33

Therefore, angle T is 33 degrees, angle Y=15+33=48 degrees and angle R=33*3=99 degrees

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3 years ago

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lys-0071 [83]

The answer would be B.

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3 years ago

Read 2 more answers

Several years ago, 38% of parents who had children in grades K-12 were satisfied with the quality of education the students r

Colt1911 [192]

Answer:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by $\alpha=1-0.95=0.05$ and $\alpha/2 =0.025$ . And the critical values are:

$z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96$

The estimated proportion of people satisfied with the quality of education the students receive is given by:

$\hat p =\frac{499}{1165}= 0.428$

The confidence interval for the proportion if interest is given by the following formula:

$\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}$

And replacing the info given we got:

$0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995$

$0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564$

8 0

4 years ago