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cestrela7 [59]
3 years ago
11

Can you guys help me with that ?

Mathematics
1 answer:
aleksley [76]3 years ago
6 0
The shirts are 12.75 for 3 so we can write a ratio of \frac{12.75}{3} To get the price of the shirts, one needs to divide \frac{12.75}{3} , which will tells use what the unit price is per shirt. The price per shirt is $4.25
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Find the requested information based on the given facts. The number of transactions is 175. The fee per transaction is $2.75. De
tino4ka555 [31]

Answer:

$481.25

Step-by-step explanation:

The number of transactions is 175.

The fee per transaction is $2.75.

The total fees is calculated as:

Number of transactions × Fee per transaction

175 × $2.75

$481.25

6 0
3 years ago
Z^4-4z^3+4z^2+48=0 how to find value of z?​
Aliun [14]

There are no real solutions to solve Z. If there may be a typo or something, there are no solutions.

3 0
2 years ago
Data was collected of students’ hair color and gender. The results are in the table below (see picture) question #1: what is the
Zinaida [17]
#1:  15%
#2:  1/10 = 10%

There are 6 girls who have blonde hair out of 40 students; 6/40 = 15%.

There are 4 boys that have black hair out of 40 students; 4/40 = 1/10 = 10%.
8 0
3 years ago
Read 2 more answers
Divide completely for the question below
juin [17]

Answer:

B) 5x^2

Step-by-step explanation:

\sqrt{\frac{50x^5}{2x} }

We can divide 50 by 2, we get 25 and we can cancel out x from x^5.

Therefore, we get

\sqrt{\frac{25x^4}{1} }

= √25x^4

When we take the square root of 25, we get 5 and √x^4 = x^2.

Taking the square root, we get

= 5x^2

Answer: B) 5x^2

Thank you.

3 0
3 years ago
The travel-to-work time for residents in Ventura County is unknown. Assume the population variance is 39. How large should a sam
katen-ka-za [31]

Answer:

A sample size of 128 is needed.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.93}{2} = 0.035

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.035 = 0.965, so z = 1.81

Now, find the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population(square root of the variance) and n is the size of the sample.

How large should a sample be if the margin of error is 1 minute for a 93% confidence interval

We need a sample size of n, which is found when M = 1. We have that \sigma = \sqrt{39}. So

M = z*\frac{\sigma}{\sqrt{n}}

1 = 1.81*\frac{\sqrt{39}}{\sqrt{n}}

\sqrt{n} = 1.81\sqrt{39}

(\sqrt{n})^2 = (1.81\sqrt{39})^2

n = 127.8

Rounding up

A sample size of 128 is needed.

7 0
3 years ago
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