Answer:
sone miyuki #4454 ALSO I DONT KNOWWW I CANT SEE THE IMAGE
Answer:
a)
b) 
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Part a
Let X the random variable that represent the weights of a population, and for this case we know the distribution for X is given by:
Where
and
We are interested on this probability
And the best way to solve this problem is using the normal standard distribution and the z score given by:
If we apply this formula to our probability we got this:
And we can find this probability like this:
And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.
Part b
For this case we select a sample size of n =32. Since the distribution for X is normal then the distribution for the sample mean
is given by:
And the new z score would be:



Answer:
π(6 cm) (10 cm)
Step-by-step explanation:
As we know that
The formula to calculate the lateral surface area of the cone is πrl
where
r denotes the radius i.e. 6 cm
l denotes the length i.e. 10 cm
So based on the above information
The expression that shows the lateral surface area of the cone is
π(6 cm) (10 cm)
Therefore the third option is correct
Hence, the same would be relevant
Answer:
C
Step-by-step explanation:
If you have a Ti-84 series calculator, press "stat" then "Edit..." and then fill in the data table values for x and y in two lists. Then press "2nd" and "mode" to quit. Now press "stat" again and right arrow over to "calc" and press down until you find "ExpReg" and set the "Xlist" and "Ylist" that you used and you will get C as the answer. Another way to do this is to manually substitute values into all 4 equations, which is boring.