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3 years ago

Someone help? 25 points

Mathematics

2 answers:

Setler [38]3 years ago

8 0

Answer:

Triangle A

Isosceles

Triangle B

Equilateral

Triangle C

Scalene

Hope this helped

spin [16.1K]3 years ago

5 0

Answer:

A- isosceles

B- equilateral

C- scalene

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Find the missing factor B that makes the equality true. -35x^6=(-5x^2)(B)<br> B=

charle [14.2K]

Answer:

B = 7 $x^{4}$

Step-by-step explanation:

Checking the result of B

- 5x² × 7 $x^{4}$ = - 35 $x^{2+4}$ = - 35 $x^{6}$ ← Correct

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4 years ago

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X = 6 is a solution to the inequality x– 5 < 10

nikitadnepr [17]

Step-by-step explanation:

I am not sure what your problem is.

is this one line just a question to you ? is x=6 a solution ?

if that is the case then ... yes, x=6 is a solution to the inequality.

x - 5 < 10

x < 15

so, 6 < 15 is true, therefore, x=6 is a valid solution

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3 years ago

Can you solve for x for this shape?

Ilia_Sergeevich [38]

Hi my friend
6x + 1 + 20 = 9x - 6 (exterior angle of triangle)
3x = 27
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3 years ago

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What is the y-intercept of the graph that is shown below?

ch4aika [34]

Answer:

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3 years ago

Point D is the incenter of triangle BCA. If m∠FDG = 136°, what is the measure of ∠FHG?

nikdorinn [45]

Given:

Point D is incenter of ΔBCA.

m∠FDG = 136°

To find:

The measure of ∠FHG

Solution:

<em>Angle subtended by the arc at the center is twice that subtended on the remain part of the circle.</em>

$\Rightarrow m\angle FDG = 2 m\angle FHG$

Divided by 2 on both sides.

$$\Rightarrow \frac{1}{2} m\angle FDG = \frac{1}{2} \times 2 m\angle FHG$

$$\Rightarrow \frac{1}{2} m\angle FDG = m\angle FHG$

Substitute m∠FDG = 136°

$$\Rightarrow \frac{1}{2} (136^\circ)= m\angle FHG$

$$\Rightarrow 68^\circ= m\angle FHG$

The measure of ∠FHG is 68°.

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3 years ago

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