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3 years ago

Please help need an answer really fast

Mathematics

1 answer:

dimulka [17.4K]3 years ago

8 0

It would be 1 and 6/7

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Evaluate 8-2.<br>A. -16<br>B. -64<br>C. -1/64<br>D. 1/64<br>

makvit [3.9K]

I'm assuming you meant to write 8^(-2) or $8^{-2}$ where the -2 is the exponent over the 8.

If my assumption is correct, then we use the rule $a^{-b} = \frac{1}{a^b}$

So,

$a^{-b} = \frac{1}{a^b}\\\\8^{-2} = \frac{1}{8^2}\\\\8^{-2} = \frac{1}{64}$

<h3>Answer: Choice D. 1/64</h3>

8 0

2 years ago

How do you solve 6x + 8= 50

Marina CMI [18]

First start by subtracting:
50-8=42
the new equation is:
6x=42
then divide:
42/6=7
So the answer is:
x=7

Hope this helps!! :D

6 0

3 years ago

Read 2 more answers

What is the semiannual interest payments of a 30 year bond with a face value of $50 million and a stated annual interest rate of

Snowcat [4.5K]

Based on the stated annual interest rate and the face value of the bond, the semiannual payments will be $1,000,000.

<h3>How can the semiannual interest payment be found?</h3>

The formula to find the semiannual payment is:

= (Face value x Stated annual interest rate) / 2 semi-annual periods per year

Solving gives:

= (50,000,000 x 4%) / 2

= 2,000,000 / 2

= $1,000,000

Find out more on bond payments at brainly.com/question/22488444.

#SPJ1

8 0

2 years ago

math help right now plzzz HURRY NOOW NOW NOW 1 ATTACHMENTS GIVING A BRAINLIEST ANSWER ALL 3 you have to match them

mixer [17]

A. c + 7 ≤ 3
c ≤ -4
a = 2

b. c - 3 > 1
c > 4
b = 3

c. c - 7 < 3
c < 10
c = 2

7 0

4 years ago

Read 2 more answers

Consider the null hypothesis, H0: µ = 4,000, at the 1% level of significance. If the z-test statistic is calculated to be 6.00,

kow [346]

Answer:

Option B) Reject null hypothesis

Step-by-step explanation:

We are given the following in the question:

We are given the null hypothesis:

$H_0 = 4,000$

$\alpha = 0.01$

$z_{stat} = 6.00$

Two tailed z-test

Now, $z_{critical} \text{ at 0.01 level of significance } = \pm 2.58$

Since,

The calculated z-statistic does not lie in the acceptance region, we fail to accept and reject the null hypothesis.

Left-tailed z-test

Now, $z_{critical} \text{ at 0.01 level of significance } = -2.58$

Since,

$z_{stat} > z_{critical}$

We fail to accept and reject the null hypothesis.

Right-tailed z-test

Now, $z_{critical} \text{ at 0.01 level of significance } = 2.58$

Since,

$z_{stat} > z_{critical}$

We fail to accept and reject the null hypothesis.

7 0

3 years ago