Given:
A student says that the graph of the equation 
is the same as the graph of 
, only translated upwards by 8 units.
To find:
Whether the student is correct or not.
Solution:
Initial equation is
Equation of after transformation is
Now,
...(i)
The translation is defined as
...(ii)
Where, a is horizontal shift and b is vertical shift.
If a>0, then the graph shifts a units left and if a<0, then the graph shifts a units right.
If b>0, then the graph shifts b units up and if b<0, then the graph shifts b units down.
From (i) and (ii), we get
Therefore, the graph of translated left by 8 units. Hence, the student is wrong.
Answer:
I think its the third one but im not entirely sure
Step-by-step explanation:
Answer:
<7=120
<8=60
Step-by-step explanation:
<2 and <7 are alternate exterior angles. <7 and <8 are complementary sor just do 180-120 and you will get 60
x° = 14°, y° = 14°; Use vertical and supplementary angles.
Step-by-step explanation:
The image of the answer is attached below.
In the given image two lines are parallel with transversal.
(9x + 12)° and ∠1 are vertically opposite angles.
Vertically opposite angles are equal.
∠1 = (9x + 12)°
Consecutive interior angles are supplementary.
(9x + 12)° + 3x° = 180°
⇒ 12x° = 168°
⇒ x° = 14°
Sum of the adjacent angles in a line are supplementary.
3x° + (4y – 10)° = 180°
⇒ 3(14)° + 4y° – 10° = 180°
⇒ 4y° = 148°
⇒ y° = 14°
Hence, x° = 14°, y° = 14°; Use vertical and supplementary angles.
