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8_murik_8 [283]

3 years ago

6

A circular puzzle is 20 inches in diameter. All of the pieces are about the same size. You want to know about how many pieces th

ere are in the puzzle.

1 answer:

loris [4]3 years ago

4 0

Answer:

circumference

Step-by-step explanation:

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Linda has $10, Rick has &12, they both put there money together to buy a pizza that cost $14, they buy it, then someone give

prohojiy [21]

First you add 10 and 12 dollars to get 22 dollars then subtract the 14 dollars of the pizza to get 7 dollars left. Then add the other 18 given to them and your final answer adds up to 25 dollars in all. :)

6 0

2 years ago

7(x+3)=-2(x-5) <br> Help pls?

olganol [36]

Answer:

x = -11/9

Step-by-step explanation:

7(x+3)=-2(x-5)

Distribute

7x+21 = -2x+10

Add 2x to each side

7x+21 +2x = -2x+10+2x

9x +21 = 10

Subtract 21 from each side

9x +21-21 = 10-21

9x = -11

Divide each side by 9

9x/9 = -11/9

x = -11/9

3 0

3 years ago

Read 2 more answers

Help test plsss I will give the first person brainlest

Ket [755]

Answer: 306.9

Step-by-step explanation: 3.1 x 11 = 34.1 x 9 = 306.9

5 0

3 years ago

Read 2 more answers

Let F⃗ =2(x+y)i⃗ +8sin(y)j⃗ .

Alik [6]

Answer:

-42

Step-by-step explanation:

The objective is to find the line integral of $F$ around the perimeter of the rectangle with corners (4,0), (4,3), (−3,3), (−3,0), traversed in that order.

We will use <em>the Green's Theorem </em>to evaluate this integral. The rectangle is presented below.

We have that

$F(x,y) = 2(x+y)i + 8j \sin y = \langle 2(x+y), 8\sin y \rangle$

Therefore,

$P(x,y) = 2(x+y) \quad \wedge \quad Q(x,y) = 8\sin y$

Let's calculate the needed partial derivatives.

$P_y = \frac{\partial P}{\partial y} (x,y) = (2(x+y))'_y = 2\\Q_x =\frac{\partial Q}{\partial x} (x,y) = (8\sin y)'_x = 0$

Thus,

$Q_x -P_y = 0 -2 = - 2$

Now, by the Green's theorem, we have

$\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA = \int \limits_{-3}^{4} \int \limits_{0}^{3} (-2)\,dy\, dx \\ \\\phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-2y) \Big|_{0}^{3} \; dx\\ \phantom{\oint_C F \,dr = \iint_D (Q_x-P_y)\,dA}= \int \limits_{-3}^{4} (-6)\; dx = -6x \Big|_{-3}^{4} = -42$

4 0

2 years ago

What is the slope of points (4,9) (-8,-6)?

12345 [234]

Answer:

5/4

Step-by-step explanation:

(y₂ - y₁) / (x₂ - x₁)

(4,9) (-8, -6)

plug in

(-6 - 9) / (-8 - 4)

solve within parentheses

-15/-12

simplify

5/4

6 0

2 years ago

Read 2 more answers