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disa [49]
3 years ago
11

A grid shows the positions of a subway stop and your house. The subway stop is located at (–9, 7) and your house is located at (

9, –2). What is the distance, to the nearest unit, between your house and the subway stop?
A.25
B. 20
C. 30
D. 17
Mathematics
1 answer:
miv72 [106K]3 years ago
8 0
For this case, the first thing you should do is use the distance between points formula.
 We have then:
 d = root ((x2-x1) ^ 2 + (y2-y1) ^ 2)
 Substituting we have:
 d = root ((9 - (- 9)) ^ 2 + (-2-7) ^ 2)
 d = 20.1246118
 Rounding off we have:
 d = 20 units
 Answer:
 
The distance, to the nearest unit, between your house and the subway stop is:
 
B. 20
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1<br> 15<br> 3x =<br> 2<br> Circle the ratio<br> xiy<br> 6:1<br> 1:6<br> 3:2<br> 2:3
katen-ka-za [31]

Question isnt well formatted :

Answer:

1 : 6

Step-by-step explanation:

Given the question :

3x = 1/2y

3x = y/2

Multiply both sides by 2

3x * 2 = y/2 * 2

6x = y

This can be interpreted as :

y = 6 times the value of x

x = y/6

x : y

1 : 6

3 0
3 years ago
How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird
NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}

Then

Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\

Note that since

F \cap R=\varnothing, Perm(F)\cap Perm(R)\ne \varnothing

But since

B \cap R \ne \varnothing, Perm(B)\cap Perm(R)= \varnothing

and

B \cap F \ne \varnothing , Perm(B)\cap Perm(F)= \varnothing

Since

|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\

where |Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}

and

|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}

What we are looking for is the number of permutations of the 26 letters of the alphabet that do  not contain the strings fish, rat or bird, or

|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0
2 years ago
What is the inverse of f(x)=3x+6 ?
scZoUnD [109]

Answer:

\boxed{\sf \ \ f^{-1}(x)=\dfrac{x-6}{3} \ \ }

Step-by-step explanation:

hello,

we can write

fof^{-1}(x)=x \ and \ fof^{-1}(x)=f(f^{-1}(x))=3f^{-1}(x)+6 \ so\\3f^{-1}(x)+6=x \ \ subtract \ 6\\3f^{-1}(x)=x-6 \ \ divide \ \ by \ \ 3\\ f^{-1}(x)=\dfrac{x-6}{3}

hope this helps

3 0
3 years ago
What do a parallelogram and kite have in common?
grigory [225]
They both have 4 congruent sides and angles.
4 0
3 years ago
Need help! much appreciated
Volgvan

Answer:

C-D = <u>6</u>

A-B = <u>3.25</u>

D = <u>118</u>

Step-by-step explanation:

C-D = 6 because the line is the same as B-C

A-B = 3.25 because the line is the same as A-D

D = 118 because the angle of B is vertically opposite to D

7 0
3 years ago
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