Answer:
FD ≈ 252.8 feet
Step-by-step explanation:
By applying tangent rule in the given right triangle,
tan(20°) =
tan(20°) =
0.36397 =
FD =
FD = 252.77
FD ≈ 252.8 feet
In the value 9,443.2 we can spot two 4's.
One resides in the hundreds column and the other resides in the tens column.
Reduce the numbers with 3. Any expression divided by 1 remains the same.
Answer: 29.28 years
Explanation:
From Kepler's third law the square of orbital period of revolving celestial body is proportional to the cube of semi -major axis from the body it is revolving about.
P² =A³
Where, P is the orbital period in years and A is the semi-major axis in AU (Astronomical units)
It is given that, For Saturn, A = 9.5 AU. We need to find P
⇒P² = (9.5 AU)³
⇒P² = 857.38
⇒P = 29.28 years
Thus, the orbital period of Jupiter is 29.28 years around the Sun.
Answer:
2
Step-by-step explanation:
slope=rise/run=2/1=2
