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den301095 [7]
3 years ago
13

Petrol and oil are mixed in the ratio 10/1 . How many litres of oil needed to mix with 5 litres of petrol?

Mathematics
2 answers:
Dominik [7]3 years ago
8 0
1/2 ful explanation
valina [46]3 years ago
7 0

Answer:

1/2

Step-by-step explanation:

since 10petrols=1 oil

therefore 5petrols=1/2

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A package weighs 4.25 kilograms. How many grams does the package weigh?(Please Show Work :D)
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4 years ago
Determine the singular points of the given differential equation. Classify each singular point as regular or irregular. (Enter y
ludmilkaskok [199]

Answer:

Step-by-step explanation:

Given that:

The differential equation; (x^2-4)^2y'' + (x + 2)y' + 7y = 0

The above equation can be better expressed as:

y'' + \dfrac{(x+2)}{(x^2-4)^2} \ y'+ \dfrac{7}{(x^2- 4)^2} \ y=0

The pattern of the normalized differential equation can be represented as:

y'' + p(x)y' + q(x) y = 0

This implies that:

p(x) = \dfrac{(x+2)}{(x^2-4)^2} \

p(x) = \dfrac{(x+2)}{(x+2)^2 (x-2)^2} \

p(x) = \dfrac{1}{(x+2)(x-2)^2}

Also;

q(x) = \dfrac{7}{(x^2-4)^2}

q(x) = \dfrac{7}{(x+2)^2(x-2)^2}

From p(x) and q(x); we will realize that the zeroes of (x+2)(x-2)² = ±2

When x = - 2

\lim \limits_{x \to-2} (x+ 2) p(x) =  \lim \limits_{x \to2} (x+ 2) \dfrac{1}{(x+2)(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{1}{(x-2)^2}

\implies \dfrac{1}{16}

\lim \limits_{x \to-2} (x+ 2)^2 q(x) =  \lim \limits_{x \to2} (x+ 2)^2 \dfrac{7}{(x+2)^2(x-2)^2}

\implies  \lim \limits_{x \to2}  \dfrac{7}{(x-2)^2}

\implies \dfrac{7}{16}

Hence, one (1) of them is non-analytical at x = 2.

Thus, x = 2 is an irregular singular point.

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3 years ago
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Petsmart's marketing team finds in their most recent report that they sell 45 guinea pigs a
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6 0
2 years ago
Segments
Ipatiy [6.2K]

There are several ways two triangles can be congruent.

  • \mathbf{AC = BD}<em> congruent by SAS</em>
  • \mathbf{\angle ABC \cong \angle BAD}<em> congruent by corresponding theorem</em>

In \mathbf{\triangle AOL} and \mathbf{\triangle BOK} (see attachment), we have the following observations

1.\ \mathbf{AO = DO} --- Because O is the midpoint of line segment AD

2.\ \mathbf{BO = CO} --- Because O is the midpoint of line segment BC

3.\ \mathbf{\angle AOB =\angle COD} ---- Because vertical angles are congruent

4.\ \mathbf{\angle AOC =\angle BOD} ---- Because vertical angles are congruent

Using the SAS (<em>side-angle-side</em>) postulate, we have:

\mathbf{AC = BD}

Using corresponding theorem,

\mathbf{\angle ABC \cong \angle BAD} ---- i.e. both triangles are congruent

The above congruence equation is true because:

  1. <em>2 sides of both triangles are congruent</em>
  2. <em>1 angle each of both triangles is equal</em>
  3. <em>Corresponding angles are equal</em>

See attachment

Read more about congruence triangles at:

brainly.com/question/20517835

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3 years ago
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