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3 years ago

Positive fractions less than 1 ,with an interval of 1/8 between each pair of fractions

Mathematics

1 answer:

Ray Of Light [21]3 years ago

8 0

Here are some that may help: 1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8

Have a great night! Hope this helped!

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A simple random sample of size nequals81 is obtained from a population with mu equals 83 and sigma equals 27. (a) Describe the

Ivanshal [37]

Answer:

a) $\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

b) $z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

c) $z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

d) $z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

Step-by-step explanation:

For this case we know the following propoertis for the random variable X

$\mu = 83, \sigma = 27$

We select a sample size of n = 81

Part a

Since the sample size is large enough we can use the central limit distribution and the distribution for the sampel mean on this case would be:

$\bar X \sim N (\mu, \frac{\sigma}{\sqrt{n}})$

With:

$\mu_{\bar X}= 83$

$\sigma_{\bar X}=\frac{27}{\sqrt{81}}= 3$

Part b

We want this probability:

$P(\bar X>89)$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 89 we got:

$z= \frac{89-83}{\frac{27}{\sqrt{81}}}= 2$

$P(Z>2) = 1-P(Z$

Part c

$P(\bar X$

We can use the z score formula given by:

$z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}$

And if we find the z score for 75.65 we got:

$z= \frac{75.65-83}{\frac{27}{\sqrt{81}}}= -2.45$

$P(Z$

Part d

We want this probability:

$P(79.4 < \bar X < 89.3)$

We find the z scores:

$z= \frac{89.3-83}{\frac{27}{\sqrt{81}}}= 2.1$

$z= \frac{79.4-83}{\frac{27}{\sqrt{81}}}= -1.2$

$P(-1.2$

8 0

3 years ago

On section AB, whose length is 192 cm, take the point C so that AC: CB = 1: 3. The point D is taken on the AC section so that CD

jasenka [17]

Answer:

112 cm

Step-by-step explanation:

Given:

AB = 192 cm
AC : CB = 1 : 3
CD = BC/12
The distance between midpoints of AD and CB = x

Find the length of AC and CB:

AC + CB = AB
AC + 3AC = 192
4AC = 192
AC = 192/4
AC = 48 cm

Find CB:

CB = 3AC = 3*48 = 144 cm

Find the length of CD:

CD = BC/12 = 144/12 = 12 cm

Find the length of AD:

AD = AC - CD = 48 - 12 = 36 cm

Find the midpoint of AD:

m(AD) = 36/2 = 18 cm

Find the midpoint of CB:

m(CB) = AC + 1/2CB = 48 + 144/2 = 48 + 82 = 130 cm

Find the distance between the midpoints:

x = 130 - 18 = 112 cm

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Answer: Rounded to the nearest tenth is 5

4.96894409 is the exact answer

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Oksana_A [137]

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...........

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krok68 [10]

Answer:

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Step-by-step explanation:

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