2 years ago

Positive fractions less than 1 ,with an interval of 1/8 between each pair of fractions

Mathematics

1 answer:

Ray Of Light [21]2 years ago

8 0

Here are some that may help: 1/8, 2/8, 3/8, 4/8, 5/8, 6/8, 7/8

Have a great night! Hope this helped!

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WILL GIVE BRAINLIEST& 15 PTS.

kicyunya [14]

Answer:

The given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

Step-by-step explanation:

Consider the given fraction $\frac{x^3-x^2}{x^3}$

We have to reduce the fraction to the lowest terms.

Consider numerator $x^3-x^2$

We can take x² common from both the term,

Thus, numerator can be written as $x^2(x-1)$

Given expression can be rewritten as ,

$\frac{x^3-x^2}{x^3}=\frac{x^2(x-1)}{x^3}$

We can now cancel $x^2$ from both numerator and denominator,

$\Rightarrow \frac{x^2(x-1)}{x^3}=\frac{x^2(x-1)}{x^2 \cdot x}$

$\Rightarrow \frac{(x-1)}{x^2 \cdot x}=\frac{x-1}{x}$

Thus, the given fraction $\frac{x^3-x^2}{x^3}$ reduces to $\frac{x-1}{x}$

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