Answer:
Dylan delivered 140 parcels on Wednesday.
Step-by-step explanation:
On Wednesday:
On Wednesday, he delivered x parcels.
Thursday:
10% more than Wednesday, so 100 + 10 = 110% of x = 1.1x
Friday:
50% pless than on Thursday, so 100 - 50 = 50% of 1.1x = 0.5*1.1*x.
THis is equals to 77. So
Dylan delivered 140 parcels on Wednesday.
8.
33 = 2y + 1 + y - 1
Add the 1 and -1
Add the y and 2y
33 = 3y
11 = y
9, AQ = 2y + 1
2(11) + 1
22 + 1
23
AQ = 23
10, QX = y - 1
QX = 11 - 1
10
QX = 10
11. 62 = 3x - 4 + 3x - 4
Add -4 and -4
Then add 3x + 3x
62 = 6x
Divide 62 by 6x
x = 11 2/3
AB = 3x - 4
3 (11 2/3) - 4
3 * 11 2/3 = 35
35 - 4 = 31
AB = 31
Both sides are equal, so BC also equals 31
12. 206 = 3x - 4 + 3x - 4
206 = 6x
x = 34 1/3
AB = 3x - 4
AB = 3(34 1/3) - 4
AB = 103
Because AB and BC are the same, BC also equals 103.
Answer:
295/72
Step-by-step explanation:
Ok
First use the sine rule to find one value
b / sin B = c / sin C
20.2 / sin B = 18.3 / sin 38
sinB = 20.2 * sin 38 / 18.3 = 0.6796
m < B = 42.8 degrees
the other possible measure is 180 - 42.8 = 137.2 degrees
Answer:
21 box of books can be brought up by the delivery person at one time
Step-by-step explanation:
Here, we want to know the number of box of books that the delivery person could bring up at one time.
Let the number of boxes be x , so the total mass of the boxes that could come up at a time will be x * 40 = 40x lb
Let’s add this to the mass of the delivery person = 150 lb
So the total mass going inside the lift would be 150 + 40x
So we have to equate this to the maximum capacity of the lift;
150 + 40x = 1020
40x = 1020 - 150
40x = 870
x = 870/40
x = 21.75
Now since we cannot have fractional boxes, the number of boxes that could come into the lift without exceeding the maximum capacity of the lift is 21
