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3 years ago

5

Simplify (i^24)^

align="absmiddle" class="latex-formula">

1 answer:

Ann [662]3 years ago

3 0

value of above expression is 1

solution in attachment !

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Mike's Music charges $45 per hour. Tim's Tunes

klemol [59]

Answer:

Answer 4. (5 1/3 hours)

Step-by-step explanation:

240/45=5.333333333

5 0

3 years ago

Read 2 more answers

Pls help giving brbrainlyist

chubhunter [2.5K]

The fourth choice. For example, (x+2)(x-2)>0 we'll get x>2 or x<-2 because whenever you substitute x>2 for example x = 3, the value will be higher than 0 itself.

If we substitute x = 3 (for x>2)

We'll get (3+2)(3-2)>0

5(1)>0

5>0 The statement is true.

If we substitute x = -3 (for x<-2)

We'll get (-3+2)(-3-2)>0

-1(-5)>0

5>0 The statement is true.

We don't say x>2 AND x<-2, In math, we only say x>2 OR x<-2

6 0

3 years ago

Read 2 more answers

How many permutations of the 26 letters of the English alphabet do not contain any of the strings fish, rat, or bird

NARA [144]

The number of permutations of the 26 letters of the English alphabet that do not contain any of the strings fish, rat, or bird is 402619359782336797900800000

Let

$\mathcal{E}=\{\text{All lowercase letters of the English Alphabet}\}\\\\B=\overline{\{b,i,r,d\}} \cup \{bird\}\\\\F=\overline{\{f,i,s,h\}} \cup \{fish\}\\\\R=\overline{\{r,a,t\}} \cup \{rat\}\\\\FR=\overline{\{f,i,s,h,r,a,t\}} \cup \{fish,rat\}$

Then

$Perm(\mathcal{E})=\{\text{All orderings of all the elements of } \mathcal{E}\}\\\\Perm(B)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing bird}\}\\\\Perm(F)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing fish}\}\\\\Perm(R)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing rat}\}\\\\Perm(FR)=\{\text{All orderings of all the elements of } \mathcal{E} \text{ containing both fish and rat}\}\\$

Note that since

$F \cap R=\varnothing$ , $Perm(F)\cap Perm(R)\ne \varnothing$

But since

$B \cap R \ne \varnothing$ , $Perm(B)\cap Perm(R)= \varnothing$

and

$B \cap F \ne \varnothing$ , $Perm(B)\cap Perm(F)= \varnothing$

Since

$|\mathcal{E} |=26 \text{, then, } |Perm(\mathcal{E})|=26! \\\\|B|=26-4+1=23 \text{, then, } |Perm(B)|=23!\\\\|F|=26-4+1=23 \text{, then, } |Perm(F)|=23!\\\\|R|=26-3+1=24 \text{, then, } |Perm(R)|=24!\\\\|FR|=26-7+2=21 \text{, then, } |Perm(FR)|=21!\\$

where $|Perm(X)|=\text{number of possible permutations of the elements of X taking all at once}$

and

$|Perm(F) \cup Perm(R)| = |Perm(F)| + |Perm(R)| - |Perm(FR)|\\= 23!+24!- 21! \text{ possibilities}$

What we are looking for is the number of permutations of the 26 letters of the alphabet that do not contain the strings fish, rat or bird, or

$|Perm(\mathcal{E})|-|Perm(B)|-|Perm(F)\cup Perm(R)|\\= 26!-23!-(23!+24!- 21!)\\= 402619359782336797900800000 \text{ possibilities}$

This link contains another solved problem on permutations:

brainly.com/question/7951365

6 0

3 years ago

Can somebody explain to me how to do this

11111nata11111 [884]

Answer:below hopes it helps the link should help aswell

Step-by-step explanation:

https://mathsolver.microsoft.com/en/solve-problem/%60frac%7B%2010%20%7B%20q%20%20%7D%5E%7B%205%20%20%7D%20%20%20%7B%20w%20%20%7D%5E%7B%207%20%20%7D%20%20%20%20%7D%7B%202%20%7B%20w%20%20%7D%5E%7B%203%20%20%7D%20%20%20%20%7D%20%20%20%60frac%7B%204%20%7B%20%60left(%20%7B%20q%20%20%7D%5E%7B%206%20%20%7D%20%20%20%60right)%20%7D%5E%7B%202%20%20%7D%20%20%20%20%7D%7B%20%20%7B%20w%20%20%7D%5E%7B%20-5%20%20%7D%20%20%20%20%7D

3 0

3 years ago

Use the graphing tool to create a histogram of Gretchen’s data. Use eight bins for your histogram.

lozanna [386]

The number of bins in the histogram determines the width of the bins and

the frequency (number of members) in a bin.

Please find attached the graph of the histogram of Gretchen's data created with MS Excel.

<h3 /><h3>Method used to create the histogram of Gretchen's data</h3>

Given:

The table from Gretchen's data is presented as follows;

$\begin{tabular}{|c|c|} \underline{ Member}& \underline{Number of Days}\\x_1&2\\x_2&4\\x_3&7\\x_4&8\\x_5&12\\x_6&15\\x_7&10\\x_8&7\\x_9&9\\x_{10}&6\\x_{11}&13\\x_{12}&3\\x_{13}&8\\x_{14}&10\\x_{15}&10\end{array}\right]$

The required number of bins = 8 bins

The steps to create the histogram using MS Excel;

Enter the 15 dataset for the number of days as presented in the above table in a column on the worksheet.

Select the dataset entered into the cells from above then select the Insert menu.

In the Chart section of the insert menu click on the Histogram icon to view the quick options for histograms type charts.

Select the Histogram option from the drop down menu from the quick options for histograms, to create an histogram chart.

Right-click the histogram created from the previous step, then select Format Chart Area from the pop up menu.

In the Format Chart Area task pane, click on the arrow next to Chart Options, then select Horizontal Axis from the options menu.

Click on the histogram icon under Axis Options, then click on arrow button besides Axis Option sub menu, to display the axis options.

Click on the Number of bins radio button then enter 8, to create an histogram having 8 bins.

The histogram of Gretchen's data having eight bins created with MS Excel is attached.

Learn more about creating a histogram chart here:

brainly.com/question/25069221

brainly.com/question/4601962

5 0

2 years ago