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Rama09 [41]
3 years ago
10

Solve the inequality, then identify the graph of the solution 2x-1>x+2

Mathematics
1 answer:
Andreas93 [3]3 years ago
7 0

Answer:

second choice!

Step-by-step explanation:

2x-1 > x+2

[subtract x from both sides]

x-1 > 2

[add 1 to each side]

x > 3

- - - - -

our answer, to fit the inequality, should be:

- dot on the positive 3

- open dot on the line

- the right side of the dot should be highlighted

now choose the second graph since it fits all the requirements!

if i'm wrong pls let me know and always double check bc sometimes im dumb yeah <//3

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Read 2 more answers
A total of $76,000 is to be​ invested, some in bonds and some in certificates of deposit​ (CDs). If the amount invested in bonds
Anestetic [448]

Answer:

The amount invested as certificates of deposit is $ 35,000 and The amount invested as bonds is  $ 41,000

Step-by-step explanation:

Given as :

The total amount to be invested as bonds and certificates of deposit (CD) = $76,000

Let the amount invested as bonds = $ x + $6000

And The amount invested as CD = $ x

Now, According to question

The amount invested as CD + The amount invested as bonds = $ x  + $ x + $6000

Or, $ x  + $ x + $6000 = $76,000

Or, $ 2x = $76,000 - $6000

So,  $ 2x = $70,000

∴  x = \frac{70000}{2} = $ 35,000

And $ x + $6000 = $ 35,000 + $6000 = $ 41,000

Hence The amount invested as certificates of deposit is $ 35,000 and The amount invested as bonds is  $ 41,000    Answer

4 0
3 years ago
An investment services company experienced dramatic growth in the last two decades. The following models for the company's reven
zlopas [31]

Answer: a) 138.32 and b) 35 years approx.

Step-by-step explanation:

Since we have given that

R(t)=21.4e^{0.13t}\\\\C(t)=18.6e^{0.13t}

So, Profit is given by

Profit=R(t)-C(t)\\\\Profit=21.4e^{0.13t}-18.6e^{0.13t}\\\\Profit=e^{0.13t}(21.4-18.6)\\\\Profit=2.8e^{0.13t}

Difference in years of 1990 and 2020=30

So, Profit becomes :

P(30)=2.8e^{0.13\times 30}\\\\P(30)=2.8\times 49.40\\\\P(30)=138.32

(b) How long before the profit found in part (a) is predicted to double? (Round your answer to the nearest whole number.) years after 1990.

So, profit doubles , we get :

138.32\times 2=2.8e^{0.13t}\\\\276.65=2.8e^{0.13t}\\\\\dfrac{276.65}{2.8}=e^{0.13t}\\\\98.80=e^[0.13t}\\\\\ln 98.80=0.13t\\\\4.593=0.13t\\\\\dfrac{4..593}{0.13}=t\\\\35.33=t

Hence, a) 138.32 and b) 35 years approx.

6 0
3 years ago
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