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antoniya [11.8K]
2 years ago
15

How can you tell by looking at the coordinates of the two triangles that Δ A'B'C' is a 180° rotation of Δ ABC? A) The coordinate

s cannot prove a 180° rotation. B) The y-coordinates of the points on ΔA'B'C' have opposite signs from the corresponding points on ΔABC. C) The x-coordinates of the points on ΔA'B'C' have opposite signs from the corresponding points on ΔABC. D) Both the x and y coordinates of the points on ΔA'B'C' have opposite signs from the corresponding points on ΔABC.
Mathematics
2 answers:
MariettaO [177]2 years ago
7 0

under a rotation about the origin of 180°

a point (x, y ) → (- x, - y )

hence D is correct, both the x and y coordinates of the points on ΔA'B'C' have opposite signs from the corresponding points on ΔABC


denis23 [38]2 years ago
5 0

Answer:

Its D

Step-by-step explanation:

Both coordinates  have opposite signs.

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3 years ago
Aldo deposits $6000 into an account that pays simple interest at a rate of 4% per year. how much interest will he be paid in the
beks73 [17]
I = P x R x T
I = 6000 x .04 x 2
I = $480

He will be paid $480 interest in the first two years
3 0
3 years ago
2. The ratio of
denpristay [2]

Answer:

<h2>3500</h2>

Step-by-step explanation:

Given the  ratio of  the profit, cost of  materials and labour  in the production of

an article to be 5:7:13 respectively, total ratio = 5+7+13 = 25

If the cost of labour is x, the cost of material will be 840+x (since the  cost of materials is Le  840 more than that of  labour)  .

Let the total cost of producing the article be y.

Cost of labour = 13/25 * y = x

Cost of labour  = 13y/25 = x.................... 1

Cost of material = 7/25*y = 840+x

Cost of material = 7y/25 = 840+x ..................... 2

From 1, 13y = 25x

x = 13y/25 ................... 3

Substituting equation 3 into 2:

7y/25 = 840+x

7y/25 = 840+13y/25

collect the like terms:

7y/25 - 13y/25 = 840

-6y/25 = 840

-6y = 25*840

y = 25*840/6

y = 3,500

<em>Hence the total cost of producing the article is 3500</em>

4 0
3 years ago
Lou has an account with $10,000 which pays 6% interest compounded annually. If to that account, Lou deposits $5,000 at the begin
katovenus [111]

Answer:

Option d. $22154 is the right answer.

Step-by-step explanation:

To solve this question we will use the formula A=P(1+\frac{r}{n})^{nt}

In this formula A = amount after time t

                        P = principal amount

                        r = rate of interest

                       n = number of times interest gets compounded in a year

                        t = time

Now Lou has principal amount on the starting of first year = 10000+5000 = $15000

So for one year A=15000(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 15000(1+.06)^{1}

= 15000(1.06) = $15900

After one year Lou added $5000 in this amount and we have to calculate the final amount he got

Now principal amount becomes $15900 + $ 5000 = $20900

Then putting the values again in the formula

A=20900(1+\frac{\frac{6}{100}}{1})^{1\times1}

= 20900(1+.06)^{1}

= 20900(1.06)=22154

So the final amount will be $22154.

3 0
3 years ago
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