Y= -2/3 +6 bc...
(-3,8)
y=mx+b
8= -2/3(-3) +b
8=2+b
-2 -2
6=b
Answer:
The sum =105
Step-by-step explanation:
It is given that, finite sequence 3, 7, 11, ..., 27.
<u>Points to remember</u>
1). For a finite sequence sum of n term is given by
Sum = n/2[first term + last term]
2). nth term of of an AP
tₙ = a + (n - 1)d
Where a - First term
d - common difference
<u>To find the number of terms in the given sequence</u>
Here a = 3 and d = 7 - 3 = 4
tₙ = a + (n - 1)d
27 = 3 + (n - 1)*4
4(n -1) = 27 - 3 = 24
n - 1 = 24/4 = 6
n = 6 +1 =7
<u>To find the sum</u>
Sum = n/2[first term + last term]
= 7/2[3 + 27]
= 7/2[30] = 7 * 15
= 105
Let the terms be
a , a+d, a+2d, a+3d, a+4d a + 5d
so a = -20
and a + 5d = 20
-20 + 5d = 20
5d = 40 so
d = 8
-20,-12,-4,4,12,20 is the required sequence.
3(6-7x)=-(x+2)
Use distributive property
18-21x = -x -2
Add x on both sides
18-20x = -2
Subtract 18 from both sodes
-20x= -20
Divide
Final Answer: x=1
Answer:
C. y = 8x
Step-by-step explanation:
When x = 1
y = 8(1) = 8
when x = 2
y = 8(2) = 16
x increased by 1
y increased by 8
