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diamong [38]
3 years ago
7

PLS HELP Round the square root of 426 to the nearest thousandth

Mathematics
1 answer:
Arada [10]3 years ago
7 0

Answer:

20.640

Step-by-step explanation:

√426 ≈ 20.6397674406

The digit in the ten-thousandths place (bold) is more than 4 so 1 needs to be added to the thousandths place to round the number. Then, 39 thousandths becomes 40 thousandths, and the rounded number is ...

... 20.640

_____

Since you are asked to round to thousandths, you must show the thousandths digit of the rounded number, even though it is zero. This identifies the number as having precision to thousandths, even though it can be expressed using only hundredths.

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Answer: $12,000

Step-by-step explanation:

Miguel makes 6% on every sale he makes and wants to make $600 in commissions.

The amount he needs to sell is therefore the amount that has $600 as 5% of it.

Assume the amount of insurance needed is x.

x * 5% = 600

x = 600 / 5%

x = $12,000

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3 years ago
If a pair of jeans cost 45 dollars before the sale and the sale is taking 9 dollars off of the original price what was the perce
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Answer:

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Step-by-step explanation:

A pair of jeans cost $45  before the sale.

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\dfrac{45}{9}=\dfrac{100}{x}

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45\cdot x=9\cdot 100\\ \\45x=900\\ \\x=\dfrac{900}{45}\\ \\x=20\%

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The intersection of roads M and N creates a 41.4 degree angle. What are the complimentary and supplementary angles of this inter
astra-53 [7]
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Ava read 126 books in 12 months. How many books per month did she read? Show your work
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2 years ago
I NEED HELP FAST what is y+1=5/6(x-2) in standard form?
Irina18 [472]

Answer:

\large\boxed{5x-6y=16}

Step-by-step explanation:

The standard form of an equation of a line:

Ax+By=C

We have the equation in the point-slope form. Convert:

y+1=\dfrac{5}{6}(x-2)\qquad\text{multiply both sides by 6}\\\\6y+6=6\!\!\!\!\diagup^1\cdot\dfrac{5}{6\!\!\!\!\diagup_1}(x-2)\\\\6y+6=5(x-2)\qquad\text{use the distributive property}\\\\6y+6=(5)(x)+(5)(-2)\\\\6y+6=5x-10\qquad\text{subtract 6 from both sides}\\\\6y+6-6=5x-10-6\\\\6y=5x-16\qquad\text{subtract}\ 5x\ \text{from both sides}\\\\-5x+6y=5x-5x-16\\\\-5x+6y=-16\qquad\text{change the signs}\\\\\boxed{5x-6y=16}

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3 years ago
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