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3 years ago

Which term best describes the tip of a needle

Mathematics

1 answer:

Marina CMI [18]3 years ago

5 0

A point is the best term to use to describe the tip of a needle.

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Matrices and determinants What is 4c?

ddd [48]

Answer:

Answer is D.

Step-by-step explanation:

do 4 times every value in the ( )

5 0

2 years ago

Read 2 more answers

Suppose A = {1, 7, 13, 17, 21, 25} and B = {7, ,14, 21, 28, 35, 42}. What is A∩B?

Lubov Fominskaja [6]

$A\cap B=\{7,21\}$

8 0

3 years ago

The cross-sectional areas of a right triangular prism and a right cylinder are congruent. The right triangular prism has a heigh

expeople1 [14]

Answer:

The correct answer is:

The volume of the triangular prism is equal to the volume of the cylinder

Step-by-step explanation:

Given that there are two figures

1. A right triangular prism and

2. Right cylinder

Area of cross section of prism is equal to Area of cross section of cylinder.

Let this value be A.

Also given that Height of prism = Height of cylinder = 6

Volume of a prism is given as:

$V_{Prism} = \text{Area of cross section} \times Height$

$V_{Prism} = A \times 6 ........ (1)$

Cross section of cylinder is a circle.

Area of circle is given as: $\pi r^{2}$

Area of cross section, A = $\pi r^{2}$

Volume of cylinder is given as:

$V_{Cylinder} = \pi r^{2} h\\\Rightarrow V_{Cylinder} = A \times h\\\Rightarrow V_{Cylinder} = A \times 6 ...... (2)$

From equations (1) and (2) we can see that

$V_{Prism}=V_{Cylinder}$

Hence, the correct answer is:

Volume of prism is equal to the volume of cylinder.

3 0

2 years ago

Y = x - 3 and y = 7x + 3 on a graph

dusya [7]

Answer:

Y+x-3 and y=7x+3 on a graph

Step-by-step explanation:

2948 28942

4 0

2 years ago

What is the equation of line perpendicular to y-3=-4(x+2) and passee through the point (-5,7

netineya [11]

Answer: $y=\frac{1}{4}x+\frac{33}{4}$

Step-by-step explanation:

1. By definition, two slopes are perpendicular if their slopes are negative reciprocals of each other. So, let's find the slope of the other line.

2. The equation given in the problem is written in Point-slope form:

$y-y_1=m(x-x_1)$

Where m is the slope.

3. Therefore, the slope of its perpendicular line must be:

$m=\frac{1}{4}$

4. You have the point (-5,7), so you can substitute it into the point-slope formula to find the equation of the new line:

$y-7=\frac{1}{4}(x+5)$

5. In slope intercept form is:

$y=\frac{1}{4}x+\frac{5}{4}+7\\y=\frac{1}{4}x+\frac{33}{4}$

7 0

3 years ago